检查文件是 32 位还是 64 位 - 在 Windows 上

Question

我正在我的 64 位机器上编译一个程序，但我不确定它是生成 32 位还是 64 位输出。如何在 Windows 上检查文件是 32 位还是 64 位？

Answer 1

You can use GNUfile for windows.
You can run the app thru PEID Lastly (and preferred- less room for error) With either Visual Studio C++ (at least express edition minimum) or the Platform SDK installed you can use dumpbin /headers to look at the PE header values.

The first value in the file header tells you the architecture: either 0x14C for x86 or 0x8664 for x64

Answer 2

Just run it and have a look at the Processes tab in Windows Task Manager. If there is a *32 suffix after the process name, it's 32-bit, otherwise it's 64-bit (provided you're on a 64-bit OS).

Answer 3

You could run the 'file' command from linux in a cygwin environment to test.

You could also place some debug statement like 'print sizeof(int)' (schematically) to check.

Answer 4

You may use EXE Explorer by MiTec, a small free tool. It also displays many other properites of the binary file it checks.

I had the same question as the original poster and the EXE Explorer works for me quite well.

Answer 5

http://ntinfo.biz/ - Detect It Easy.

Or just GNU Binutils objdump -f my.exe