电话链接iPhone SDK-如何返回到应用

Question

Is it possible to return to my app once a phone link ( tel: ) has been clicked, and opened using

[[UIApplication sharedApplication] openURL:xyz]

For example, when the user ends the call?

Thanks

Answer 1

不，很遗憾，无法实现这一目标，因为单击链接始终会首先终止您的应用程序，然后启动新应用程序。

Answer 2

No. Although if you store your state using NSUserDefaults (or other means) you can return to the same point where you left; the user will have to relaunch your app to do this. This approach is recommended in the Human Interface Guidelines.