对基类模板成员函数的模棱两可的访问

Question

In Visual Studio 2008, the compiler cannot resolve the call to SetCustomer in _tmain below and make it unambiguous:

template <typename TConsumer>
struct Producer
{
    void SetConsumer(TConsumer* consumer) { consumer_ = consumer; }

    TConsumer* consumer_;
};

struct AppleConsumer
{
};

struct MeatConsumer
{
};

struct ShillyShallyProducer : public Producer<AppleConsumer>,
                              public Producer<MeatConsumer>
{
};

int _tmain(int argc, _TCHAR* argv[])
{
    ShillyShallyProducer producer;
    AppleConsumer consumer;
    producer.SetConsumer(&consumer);   //  <--- Ambiguous call!!

    return 0;
}

This is the compilation error:

// error C2385: ambiguous access of 'SetConsumer'
//    could be the 'SetConsumer' in base 'Producer<AppleConsumer>'
//    or could be the 'SetConsumer' in base 'Producer<MeatConsumer>'

I thought the template argument lookup mechanism would be smart enough to deduce the correct base Producer . Why isn't it?

I could get around this by changing Producer to

template <typename TConsumer>
struct Producer
{
    template <typename TConsumer2>
    void SetConsumer(TConsumer2* consumer) { consumer_ = consumer; }

    TConsumer* consumer_;
};

and call SetConsumer as

    producer.SetConsumer<AppleConsumer>(&consumer);   // Unambiguous call!!

but it would be nicer if I didn't have to...

Answer 1

I thought the template argument lookup mechanism would be smart enough to deduce the correct base Producer.

This hasn't to do with templates, it comes from using multiple base classes - the name lookup is already ambiguous and overload resolution only takes place after that.

A simplified example would be the following:

struct A { void f()    {} };
struct B { void f(int) {} };
struct C : A, B {};

C c;
c.f(1); // ambiguous

Workarounds are explicitly qualifying the call or to introduce the functions into the derived classes scope:

 struct ShillyShallyProducer : public Producer<AppleConsumer>,
                               public Producer<MeatConsumer>
 {
     using Producer<AppleConsumer>::SetConsumer;
     using Producer<MeatConsumer >::SetConsumer;
 };

Answer 2

You can just use explicit qualification in your function call. Instead of:

producer.SetConsumer(&consumer);

try:

producer.Producer<AppleConsumer>::SetConsumer(&consumer);