我在使用a4j：commandButton和重新设置时遇到麻烦

Question

The code below show whiche thing that is failing in my appliaction. It is a quick add information form, fill out the form and submit it add a new entry into a database and synchronize my a databasle.. This is all done with ajax. The first form submission happens correctly but the second one fails to run the desired ActionListener. The second form is posting to the server though but the saveAction isn't invoke. As you will see, I'm a real beginner with this technologies ... If someone see the problem, it will be very helpfull !!

<rich:simpleTogglePanel id="quickaddActivitySimpleToogle"
 switchType="client" 
 opened="false"
 label="#{lang.activityModule_quickAdd_panelTitle}">
<p><a4j:form id="quickAddForm">
 <h:outputLabel for="activityNameInput"
  value="#{lang.activity_name_dp}" />
 <h:inputText id="activityNameInput"
  value="#{activityController.quickActivityAdd.name}">
 </h:inputText>
 <rich:spacer width="20px" />

 <h:inputHidden id="activityInternalNameInput"
  value="#{activityController.quickActivityAdd.internalName}" />
 <rich:spacer width="20px" />
 <a4j:commandButton id="activityQuickAddFormSubmitBtn"
  reRender="activityListTable,quickAddForm"
  actionListener="#{activityController.saveActivity}" 
  value="#{lang.saveBtn_header}" />
</a4j:form></p></rich:simpleTogglePanel>

Thanks in advance.

ollie314

Answer 1

1. I'd suggest putting <a4j:form> as the most outer element
2. put immediate="true" on the commandButton to bypass validation
3. don't reRender the whole form - add a <h:panelGroup> inside, and rerender it instead.