jQuery运行时错误：预期对象
[英]Jquery runtime error: object expected
问题描述
The Jquery script that controls my tabcontainer gives an "object expected" runtime error. 
控制我的tabcontainer的Jquery脚本给出了一个“期望的对象”运行时错误。 I honestly can't find the reason why: 老实说，我找不到原因：
$(document).ready(function() {
//When page loads...
$(".tab_content").hide(); //Hide all content
$("ul.tabs li:first").addClass("active").show(); //Activate first tab
$(".tab_content:first").show(); //Show first tab content
//On Click Event
$("ul.tabs li").click(function() {
$("ul.tabs li").removeClass("active"); //Remove any "active" class
$(this).addClass("active"); //Add "active" class to selected tab
$(".tab_content").hide(); //Hide all tab content
var activeTab = $(this).find("a").attr("href"); //Find the href attribute value to identify the active tab + content
$(activeTab).fadeIn(); //Fade in the active ID content
return false;
});
});
Has it something to do with the stylesheet? 与样式表有关吗？
3 个解决方案
解决方案1
3 已采纳 2010-04-26 19:31:58
i think you want to remove you var from a selector 我认为您想从选择器中删除var
activeTab.fadeIn(); //Fade in the active ID content
If you are getting an error @ $(document).ready(function() { remember to include the jQuery script. 如果您在@ $(document).ready(function() {遇到错误，请记住包括jQuery脚本。
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js" type="text/javascript"></script>
解决方案2
3 2010-04-26 19:39:48
Your code works in this html page; 您的代码在此html页面中有效；
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js" type="text/javascript"></script>
<script>
$(document).ready(function() {
//When page loads...
$(".tab_content").hide(); //Hide all content
$("ul.tabs li:first").addClass("active").show(); //Activate first tab
$(".tab_content:first").show(); //Show first tab content
//On Click Event
$("ul.tabs li").click(function() {
$("ul.tabs li").removeClass("active"); //Remove any "active" class
$(this).addClass("active"); //Add "active" class to selected tab
$(".tab_content").hide(); //Hide all tab content
var activeTab = $(this).find("a").attr("href"); //Find the href attribute value to identify the active tab + content
$(activeTab).fadeIn(); //Fade in the active ID content
return false;
});
});
</script>
</head>
<body>
<ul class="tabs">
<li><a href="#one">Tab One</a></li>
<li><a href="#two">Tab Two</a></li>
</ul>
<div id="one" class="tab_content">Tab One Content</div>
<div id="two" class="tab_content">Tab Two Content</div>
</body>
</html>
so it must be soemthing else other that the code you show? 因此，除了显示的代码外，还必须有其他东西吗？
解决方案3
1 2010-04-26 19:28:26
Editted as I was wrong first time :-) 第一次编辑是因为我错了:-)
Your problem is these lines: 您的问题是这些行：
var activeTab = $(this).find("a").attr("href"); //This will return a string value
$(activeTab).fadeIn(); //Meaning this will fail
You need to change the selector for activeTab to get the .tab_content which you want to show. 您需要更改activeTab的选择器，以获取要显示的.tab_content。
I assume the href value is contained within the .tab_content somewhere. 我假设href值包含在.tab_content中。
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