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Linux服务和cron作业的源代码

[英]Linux service and Source for cron job

原文 2010-04-27 17:13:12 6 2 linux/ service/ init.d

I am new to linux and writing a service in C++ which spawns multiple threads and I am starting the service by calling it from init.d, but how should I send the terminate signal to my application from the script , so that my service terminates all the threads and exits. 我是Linux的新手，并用C ++编写了一个服务，该服务产生了多个线程，我正在通过从init.d调用它来启动该服务，但是我应该如何从脚本向我的应用程序发送终止信号，以便我的服务可以终止所有服务线程和出口。

And also where can I find the source code for any linux services. 而且在哪里可以找到任何linux服务的源代码。 eg /etc.init.d/rc5.d/S14cron . 例如/etc.init.d/rc5.d/S14cron。 It will be helpful in understanding how to implement a service. 这将有助于理解如何实施服务。

2 个解决方案

The classic reference for this kind of question is Steven's "Advanced Programming in the UNIX Environment". 关于此类问题的经典参考文献是Steven的“ UNIX环境中的高级编程”。 You can find the source code to this text book here . 您可以在此处找到该教科书的源代码。

Depends what your application does. 取决于您的应用程序做什么。

Personally I'd keep a thread just for handling signals and call sigprocmask in the other threads to stop signals being delivered to them. 我个人将保留一个仅用于处理信号的线程，并在其他线程中调用sigprocmask以停止将信号传递给它们。

The main thread / signal handling thread (it is usually a good idea to make this the main thread) can then send a message to its threads to tell them to finish what they're doing and quit. 然后，主线程/信号处理线程（通常使它成为主线程是一个好主意），然后可以向其线程发送一条消息，以告诉它们完成其操作并退出。

Alternatively, if you like the principle of crash-only, you could just call exit_group and be done with it :) 另外，如果您喜欢仅崩溃的原理，则可以调用exit_group并完成它:)