如何grep具有特定格式的行
[英]How to grep lines having specific format
问题描述
I have got a file with following format. 
我有以下格式的文件。
1234, 'US', 'IN',......
324, 'US', 'IN',......
...
...
53434, 'UK', 'XX', ....
...
...
253, 'IN', 'UP',....
253, 'IN', 'MH',....
Here I want to extract only those lines having 'IN' as 2nd keyword. 在这里，我只想提取那些以“ IN”作为第二个关键字的行。 ie 即
253, 'IN', 'UP',....
253, 'IN', 'MH',....
Can any one please tell me a command to grep it. 谁能告诉我一个命令来grep它。
2 个解决方案
解决方案1
2 已采纳 2010-05-02 09:42:18
grep -E ^[^,]*,\\ \\'IN\\',.+\\$ FILENAME grep -E ^ [^，] *，\\ \\'IN \\'，。+ \\ $文件名
That should do the trick! 这应该够了吧！
解决方案2
2 2010-05-02 09:44:33
这有效：
egrep "^[0-9]+, 'IN'"
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