从时间戳超过一天的MySQL表中删除行？

Question

I found the exact same question here .

But it isn't working for me. I've modified it a bit, manipulated it, and I can't figure it out. I'm trying to remove rows that are over a day old. Here is my code:

if (isset($_POST['prune'])) {

    $sql = "DELETE FROM logs WHERE time < date('now', '-1 days')";
    mysql_query($sql);

    echo 'Logs older than one day removed.';    

    }

Fairly simple question I suppose, but its bugging the hell out of me. I would appreciate any help.

In case it makes a difference, the column is a TIMESTAMP type.

EDIT: Apparently I'm an idiot. The question I linked you to relates to SQLite3. So now my question is, how can I do this in MySQL?

Answer 1

您可以减去一个间隔：

DELETE FROM logs WHERE time < now() - interval 1 day

Answer 2

That answer was IIRC for SQLite3. You're using MySQL which does not support this syntax.

You want to use DATE_ADD() function (example below not tested but should work):

DELETE FROM logs WHERE time < TIMESTAMPADD(DAY,-1,NOW());

Answer 3

In my case, only the

timestampadd

in positive direction works when running through an asc ordered date calendar:

    if (urldecode ($aUrl['Select']) == '>')
        $this-> db-> where ('konzertdatum >', 'TIMESTAMPADD(DAY, 1, "'.  $id . '") ', false) ;
    else 
        $this-> db-> where ('konzertdatum < ', 'TIMESTAMPADD(DAY, -1, "'.  $id . '") ', false) ;

In negative direction ( -1) , the timestamp goes back to the very first entry. I also tried not to use CodeIgniter, but the same consequence.

Summing up, +1 as parameter for timestampadd works, -1 works for the second lowest entry (then jumping back to the first one. But it fails when I step further away from the first date.