[英]PHP: How to overwrite values in one array with values from another without adding new keys to the array?
I have an array with default settings, and one array with user-specified settings. 我有一个默认设置的数组,以及一个具有用户指定设置的数组。 I want to merge these two arrays so that the default settings gets overwritten with the user-specified ones.
我想合并这两个数组,以便用用户指定的数组覆盖默认设置。
I have tried to use array_merge
, which does the overwriting like I want, but it also adds new settings if the user has specified settings that doesn't exist in the default ones. 我曾尝试使用
array_merge
,它可以像我想的那样进行覆盖,但如果用户指定了默认设置中不存在的设置,它还会添加新设置。 Is there a better function I can use for this than array_merge
? 有没有比
array_merge
更好的功能呢? Or is there a function I can use to filter the user-specified array so that it only contains keys that also exist in the default settings array? 或者是否有一个函数可用于过滤用户指定的数组,以便它只包含默认设置数组中也存在的键?
Example of what I want 我想要的例子
$default = array('a' => 1, 'b' => 2);
$user = array('b' => 3, 'c' => 4);
// Somehow merge $user into $default so we end up with this:
Array
(
[a] => 1
[b] => 3
)
You can actually just add two arrays together ( $user+$default
) instead of using array_merge
. 实际上你可以只添加两个数组(
$user+$default
)而不是使用array_merge
。
If you want to stop any user settings that don't exist in the defaults you can use array_intersect_key
: 如果要停止默认设置中不存在的任何用户设置,可以使用
array_intersect_key
:
Returns an associative array containing all the entries of array1 which have keys that are present in all arguments
返回一个关联数组,其中包含array1的所有条目,这些条目具有所有参数中都存在的键
$default = array('a' => 1, 'b' => 2);
$user = array('b' => 3, 'c' => 4);
// add any settings from $default to $user, then select only the keys in both arrays
$settings = array_intersect_key($user + $default, $default);
print_r($settings);
Array
(
[b] => 3
[a] => 1
)
The keys/values (and order) are selected first from $user
in the addition, which is why b
comes before a
in the array, there is no a
in $user
. 键/值(和顺序)从第一选择
$user
在加法,这就是为什么b
到来之前a
阵列中,没有a
在$user
。 Any keys not defined in $user
that are defined in $default
will then be added to the end of $user
. 在
$user
中定义的任何未在$default
中定义的键将被添加到$user
的末尾。 Then you remove any keys in $user + $default
that aren't defined in $default
. 然后删除
$user + $default
中未在$default
定义的任何键。
It's probably simplest to just loop over the keys in the default-settings array, if you only want to consider those. 如果你只想考虑那些,那么在default-settings数组中循环键可能是最简单的。 So you can do something like this:
所以你可以这样做:
foreach ($default_settings AS $key => $default_value)
{
if (array_key_exists($key, $user_settings))
{
$combined_settings[$key] = $user_settings[$key];
}
else
{
$combined_settings[$key] = $default_value;
}
}
foreach($default as $key=>$val){
if (isset($user[$key]))
{
$settings[$key] = $user[$key];
} else {
$settings[$key] = $default[$key];
}
}
I think this is what you want. 我想这就是你想要的。
foreach($user_settings as $key=>$val){
$global_settings[$key] = $val;
}
? ?
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