typedef在C中存储指针

Question

The Size of pointer depends on the arch of the machine.

So sizeof(int*)=sizeof(int) or sizeof(int*)=sizeof(long int)

I want to have a custom data type which is either int or long int depending on the size of pointer.

I tried to use macro #if, but the condition for macros does not allow sizeof operator.

Also when using if-else, typedef is limited to the scope of if.

if((sizeof(int)==sizeof(int *)){
  typedef int ptrtype;
}
else{
  typedef long int ptrtype;
}
//ptrtype not avialble here

Is there any way to define ptrtype globally?

Answer 1

在C99中，您可以使用intptr_t 。

Answer 2

The traditional way to do this used to be to use GNU autoconf (or similar) to set up some defines such as SIZEOF_VOIDPTR , but if you have a sufficiently recent compiler the type intptr_t may well be what you want. (You might need to set some compiler flags to enable C99 mode; it's in <stdint.h> .)

Answer 3

当然，使用<stdint.h>定义的intptr_t或uintptr_t 。