[英]Java: JPQL select statement
select x from X x where xaid = :a_id
--> Always 0 objects selected select x from X x where xaid = :a_id
>始终选择0个对象
Why does the above JPQL statement not work, but the one below work? 为什么上面的JPQL语句不起作用,而下面的那一个却起作用?
select a from A a where a.id = :a_id
--> a_obj select a from A a where a.id = :a_id
a_id-> a_obj
select x from X x where xa = :a_obj
--> Always correct number of objects selected select x from X x where xa = :a_obj
>总是正确选择对象的数量
Neither query throws an exception during execution, but a different number of results are obtained. 在执行过程中,两个查询都不会引发异常,但是会获得不同数量的结果。
Thanks 谢谢
Update 更新资料
I tried the following queries by using joins: 我通过使用联接尝试了以下查询:
select x from X x, xa a where xaid = :a_id
--> TopLink exception for unexpected token select x from X x, xa a where xaid = :a_id
>用于意外令牌的TopLink异常
and this: select x from X x JOIN xa a where a.id = :a_id
--> Always correct number of objects selected 然后
select x from X x JOIN xa a where a.id = :a_id
>始终正确选择对象的数量
With the latter query, I have solved the initial problem at hand. 通过后一个查询,我已经解决了手头的最初问题。 However, now I have got two queries which should work, but for some reason don't.
但是,现在我有两个查询应该可以工作,但是由于某种原因没有。
select x from X x where xaid = :a_id
--> Always 0 objects selected select x from X x where xaid = :a_id
>始终选择0个对象
select x from X x, xa a where xaid = :a_id
--> TopLink exception for unexpected token select x from X x, xa a where xaid = :a_id
>用于意外令牌的TopLink异常
Has anyone else encountered similar behaviour? 还有其他人遇到过类似的行为吗?
With the following entity for X 对于X具有以下实体
@Entity
public class EntityX {
@Id @GeneratedValue
private Long id;
@OneToOne
private EntityA a;
// ...
}
And this one for A: 这是A的:
@Entity
public class EntityA {
@Id @GeneratedValue
private Long id;
//...
}
The following JPQL query: 以下JPQL查询:
from EntityX x where x.a.id = :id
Generates the following SQL: 生成以下SQL:
select
entityx0_.id as id282_,
entityx0_.a_id as a2_282_
from
EntityX entityx0_
where
entityx0_.a_id=?
It simply works and returns as many results as expected. 它简单地工作并返回预期的结果。
Tested with Hibernate (and EclipseLink). 经过Hibernate(和EclipseLink)测试。 If this is not representative of your case, please add more details.
如果这不能代表您的情况,请添加更多详细信息。
I think you have to also bring in entity a in the first example so that it's attributes are visible. 我认为您还必须在第一个示例中引入实体a,以便其属性可见。
Something like 就像是
select x from X x join fetch x.a where x.a.id = :a_id
(I don't use JPA, I stick to HQL, so this is untested, unproven and comes without a money-back guarantee.) (我不使用JPA,我坚持使用HQL,因此这未经测试,未经验证且没有退款保证。)
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