[英]Is there a sane default for std::tr1::function?
I spent some time googling but didn't really find anything. 我花了一些时间谷歌搜索,但没有找到任何东西。 I want to be able to do this:
我希望能够这样做:
std::tr1::function<void()> foo(SOME_DEFAULT_FUNCTION_THAT_DOES_NOTHING);
//
//Some code that could possibly assign foo
//
foo();
Otherwise I have to do this: 否则我必须这样做:
std::tr1::function<void()> foo;
//
//Some code that could possibly assign foo
//
if(foo)
{
foo();
}
I realize I could just make a function that does nothing, but I am looking for some standard way of not having to deal with checking to see if the function was given a value ala the null object pattern. 我意识到我可以创建一个什么都不做的函数,但我正在寻找一些标准方法,不必处理检查以查看函数是否被赋予了null对象模式的值。
void noop() { }
Could you use a boost::optional<std::tr1::function<void()> >
? 你能使用
boost::optional<std::tr1::function<void()> >
吗? That way it allows it to be set or not, and you can use an if check to see if the function has been set. 这样它可以设置或不设置,你可以使用if检查来查看功能是否已设置。
在我的项目中,我使用
void noop(...) {}
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