在缩小期间排除调试 JavaScript 代码

Question

I'm looking into different ways to minify my JavaScript code including the regular JSMin , Packer, and YUI solutions. I'm really interested in the new Google Closure Compiler , as it looks exceptionally powerful.

I noticed that Dean Edwards packer has a feature to exclude lines of code that start with three semicolons. This is handy to exclude debug code. For instance:

;;;     console.log("Starting process");

I'm spending some time cleaning up my codebase and would like to add hints like this to easily exclude debug code. In preparation for this, I'd like to figure out if this is the best solution, or if there are other techniques.

Because I haven't chosen how to minify yet, I'd like to clean the code in a way that is compatible with whatever minifier I end up going with. So my questions are these:

1. Is using the semicolons a standard technique, or are there other ways to do it?

2. Is Packer the only solution that provides this feature?

3. Can the other solutions be adapted to work this way as well, or do they have alternative ways of accomplishing this?

4. I will probably start using Closure Compiler eventually. Is there anything I should do now that would prepare for it?

Answer 1

here's the (ultimate) answer for closure compiler :

/** @const */
var LOG = false;
...
LOG && log('hello world !'); // compiler will remove this line
...

this will even work with SIMPLE_OPTIMIZATIONS and no --define= is necessary !

Answer 2

Here's what I use with Closure Compiler. First, you need to define a DEBUG variable like this:

/** @define {boolean} */
var DEBUG = true;

It's using the JS annotation for closure, which you can read about in the documentation .

Now, whenever you want some debug-only code, just wrap it in an if statement, like so:

if (DEBUG) {
  console.log("Running in DEBUG mode");
}

When compiling your code for release, add the following your compilation command: --define='DEBUG=false' -- any code within the debug statement will be completely left out of the compiled file.

Answer 3

A good solution in this case might be js-build-tools which supports 'conditional compilation'.

In short you can use comments such as

// #ifdef debug
var trace = debug.getTracer("easyXDM.Rpc");
trace("constructor");
// #endif

where you define a pragma such as debug .

Then when building it (it has an ant-task)

//this file will not have the debug code
<preprocess infile="work/easyXDM.combined.js" outfile="work/easyXDM.js"/>
//this file will        
<preprocess infile="work/easyXDM.combined.js" outfile="work/easyXDM.debug.js" defines="debug"/>

Answer 4

Adding logic to every place in your code where you are logging to the console makes it harder to debug and maintain.

If you are already going to add a build step for your production code, you could always add another file at the top that turns your console methods into noop 's.

Something like:

console.log = console.debug = console.info = function(){};

Ideally, you'd just strip out any console methods, but if you are keeping them in anyway but not using them, this is probably the easiest to work with.

Answer 5

如果你使用的是UglifyJS2 ，你可以使用drop_console参数来移除 console.* 函数。

Answer 6

If you use the Closure Compiler in Advanced mode, you can do something like:

if (DEBUG) console.log = function() {}

Then the compiler will remove all your console.log calls. Of course you need to --define the variable DEBUG in the command line.

However, this is only for Advanced mode . If you are using Simple mode, you'll need to run a preprocessor on your source file.

Why not consider the Dojo Toolkit? It has built-in comment-based pragma's to include/exclude sections of code based on a build. Plus, it is compatible with the Closure Compiler in Advanced mode (see link below)!

http://dojo-toolkit.33424.n3.nabble.com/file/n2636749/Using_the_Dojo_Toolkit_with_the_Closure_Compiler.pdf?by-user=t

Answer 7

I use this in my React apps:

if (process.env.REACT_APP_STAGE === 'PROD')
  console.log = function no_console() {};

In other words, console.log will return nothing on prod enviroment.

Answer 8

Even though its an old question. I stumbled upon the same issue today and found that it can be achieved using CompilerOptions .

I followed this thread .

We run the compiler, from Java, on our server before sending the code to the client. This worked for us in Simple mode.

private String compressWithClosureCompiler(final String code) {
    final Compiler compiler = new Compiler();
    final CompilerOptions options = new CompilerOptions();
    Logger.getLogger("com.google.javascript.jscomp").setLevel(Level.OFF);
    if (compressRemovesLogging) {
        options.stripNamePrefixes = ImmutableSet.of("logger");
        options.stripNameSuffixes = ImmutableSet.of("debug", "dev", "info", "error",
                "warn", "startClock", "stopClock", "dir");
    }
    CompilationLevel.SIMPLE_OPTIMIZATIONS.setOptionsForCompilationLevel(options);

    final JSSourceFile extern = JSSourceFile.fromCode("externs.js", "");
    final JSSourceFile input = JSSourceFile.fromCode("input.js", code);
    compiler.compile(extern, input, options);
    return compiler.toSource();
}

It will remove all the calls to logger.debug, logger.dev...etc.etc

Answer 9

I am with @marcel-korpel. Isn't perfect but works. Replace the debug instructions before minification. The regular expression works in many places. Watch out unenclosed lines.

/console\.[^;]*/gm

Works on:

;;;     console.log("Starting process");
console.log("Starting process");
console.dir("Starting process");;;;;
console.log("Starting "+(1+2)+" processes"); iamok('good');
console.log('Message ' +
    'with new line'
);
console.group("a");
console.groupEnd();
swtich(input){
    case 1 : alert('ok'); break;
    default: console.warn("Fatal error"); break;
}

Don't works:

console.log("instruction without semicolon")
console.log("semicolon in ; string");

Answer 10

I haven't looked into minification so far, but this behaviour could be accomplished using a simple regular expression:

s/;;;.*//g

This replaces everything in a line after (and including) three semicolons with nothing, so it's discarded before minifying. You can run sed (or a similar tool) before running your minification tool, like this:

sed 's/;;;.*//g' < infile.js > outfile.js

BTW, if you're wondering whether the packed version or the minified version will be 'better', read this comparison of JavaScript compression methods .

Answer 11

I was searching for a built-in option to do this. I have not found that yet, but my favorite answer also does not require any changes to existing source code. Here's an example with basic usage .

Assume HTML file test.html with:

<html>
        <script src="hallo.js"></script>
</html>

And hallo.js with:

sayhi();
function sayhi()
{
        console.log("hallo, world!");
}

We'll use a separate file, say noconsole.js , having this from the linked answer:

console.log = console.debug = console.info = function(){};

Then we can compile it as follows, bearing in mind that order matters, noconsole.js must be placed first in the arguments:

google-closure-compiler --js noconsole.js hallo.js --js_output_file hallo.out.js

If you cat hallo.out.js you'd see:

console.log=console.debug=console.info=function(){};sayhi();function sayhi(){console.log("hallo, world!")};

And if I test with mv hallo.out.js hallo.js and reload the page, I can see that the console is now empty.

Hope this clarifies it. Note that I have not yet tested this in the ideal mode of compiling all the source code with ADVANCED optimizations, but I'd expect it to also work.

Answer 12

I've used following self-made stuf:

// Uncomment to enable debug messages
// var debug = true;

function ShowDebugMessage(message) {
    if (debug) {
        alert(message);
    }
}

So when you've declared variable debug which is set to true - all ShowDebugMessage() calls would call alert() as well. So just use it in a code and forget about in place conditions like ifdef or manual commenting of the debug output lines.