如何重置指向特定数组位置的指针？

Question

I am a brand new programming student, so please forgive my ignorance. My assignment states:

Write a program that declares an array of 10 integers. Write a loop that accepts 10 values from the keyboard and write another loop that displays the 10 values. Do not use any subscripts within the two loops; use pointers only.

Here is my code:

#include "stdafx.h"
#include <iostream>
using namespace std;

int main()
{
     const int NUM = 10;
     int values[NUM];
     int *p = &values[0];
     int x;
     for(x = 0; x < NUM; ++x, ++p)
     {
         cout << "Enter a value: ";
         cin >> *p;
     }  
     for(x = 0; x < NUM; ++x, ++p)
     {
         cout << *p << "  ";
     }
    return 0;
}

I think I know where my problem is. After my first loop, my pointer is at values[10], but I need to get it back to values[0] to display them. How can I do that?

Answer 1

You can do exactly as you did first when you assigned p :

p = &values[0];

Besides, arrays are very much like pointers (that you can't change) to statically allocated memory. Therefore, the expression &values[0] evaluates to the same thing that just values does. Consequently,

p = &values[0];

is the same as

p = values;

Answer 2

Did your assignment say that you had to print the numbers in order? If not, you could have some fun by printing them in reverse:

while (p != values)
{
    cout << *(--p) << " ";
}

(Just use this code for learning.)

Answer 3

if the assignment say that you had to print the numbers in order, should modify it as below:

for (x = 0; x < NUM; ++x, p++)
{
    cout << *(p-NUM) << "  ";
}