从Java中的字符串中提取

Question

I have a string;

String value = "(5+5) + ((5+8 + (85*4))+524)";

How can I split/extract logical values from this string inside parenthesis as;

(85*4) as one
(5+8 + one) as two
(two+524) as three
((5+5) + three) as four
...

Any idea? all is welcome

Answer 1

This cannot be done using some cleaver regular expression (regular expressions can not "count parenthesis"). Your best option is to use some parser generator and parse the string into an abstract syntax tree (AST for short).

Have a look at JFlex / JavaCUP for instance.

---

As it turns out, the CUP manual actually has an example covering your situation:

// CUP specification for a simple expression evaluator (w/ actions)

import java_cup.runtime.*;

/* Preliminaries to set up and use the scanner.  */
init with {: scanner.init();              :};
scan with {: return scanner.next_token(); :};

/* Terminals (tokens returned by the scanner). */
terminal           SEMI, PLUS, MINUS, TIMES, DIVIDE, MOD;
terminal           UMINUS, LPAREN, RPAREN;
terminal Integer   NUMBER;

/* Non-terminals */
non terminal            expr_list, expr_part;
non terminal Integer    expr;

/* Precedences */
precedence left PLUS, MINUS;
precedence left TIMES, DIVIDE, MOD;
precedence left UMINUS;

/* The grammar */
expr_list ::= expr_list expr_part 
          | 
              expr_part;

expr_part ::= expr:e 
          {: System.out.println("= " + e); :} 
              SEMI              
          ;

expr      ::= expr:e1 PLUS expr:e2    
          {: RESULT = new Integer(e1.intValue() + e2.intValue()); :} 
          | 
              expr:e1 MINUS expr:e2    
              {: RESULT = new Integer(e1.intValue() - e2.intValue()); :} 
          | 
              expr:e1 TIMES expr:e2 
          {: RESULT = new Integer(e1.intValue() * e2.intValue()); :} 
          | 
              expr:e1 DIVIDE expr:e2 
          {: RESULT = new Integer(e1.intValue() / e2.intValue()); :} 
          | 
              expr:e1 MOD expr:e2 
          {: RESULT = new Integer(e1.intValue() % e2.intValue()); :} 
          | 
              NUMBER:n                 
          {: RESULT = n; :} 
          | 
              MINUS expr:e             
          {: RESULT = new Integer(0 - e.intValue()); :} 
          %prec UMINUS
          | 
              LPAREN expr:e RPAREN     
          {: RESULT = e; :} 
          ;

Answer 2

您可以为表达式模型生成解析器，例如使用JavaCC ，然后将表达式字符串解析为表达式树。