[英]list of uids / names of System Preferences > Accounts
I could iterate from 0 to 99999 and do a getpwnam()
. 我可以从0迭代到99999并执行getpwnam()
。 However most machines have less than 5 accounts, so it's not optimal. 但是,大多数计算机的帐户少于5个,因此并非最佳选择。 I don't know what framework is responsible for this and thus I have no clue what to search for. 我不知道是什么框架负责的,因此我不知道要寻找什么。
Is there a more optimal solution that can traverse the accounts? 有没有可以遍历帐户的最佳解决方案?
Edit: Right after I posted I discovered getpwent()
for traversing accounts. 编辑:在我发布后,我发现遍历帐户的getpwent()
。
setpwent();
struct passwd *pw;
while ((pw = getpwent())) printf("%d\n", pw->pw_uid);
endpwent();
However that doesn't indicate wether an account is a System Preferences account or not. 但是,这并不表示一个帐户是否为系统偏好设置帐户。
So still how does one obtain the System Preferences accounts? 因此,仍然如何获得系统偏好设置帐户?
Edit: I have found the commandline equivalent of this, the dscl
command. 编辑:我已经找到了等效的命令行, dscl
命令。
prompt> dscl . -list /Users UniqueID
_mysql 74
_postfix 27
_spotlight 89
_sshd 75
_windowserver 88
_www 70
daemon 1
johndoe 501
nobody -2
root 0
Use getgrnam("staff")
to get a group record for the staff group. 使用getgrnam("staff")
获取人员组的组记录。 The gr_mem
member, while not explained in detail by the manpage, appears to be an array of user names terminated by a NULL pointer. gr_mem
成员虽然没有在手册页中进行详细说明,但似乎是由NULL指针终止的用户名数组。
To find which users are administrators, do the same thing with the admin group. 要查找哪些用户是管理员,请对admin组执行相同的操作。
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