在MySQL中选择多对多关系

Question

I have two tables in a MySQL database, Locations and Tags, and a third table LocationsTagsAssoc which associates the two tables and treats them as a many-to-many relationship.

Table structure is as follows:

Locations
---------
ID int (Primary Key)
Name varchar(128)

LocationsTagsAssoc
------------------
ID int (Primary Key)
LocationID int (Foreign Key)
TagID int (Foreign Key)

Tags
----
ID int (Primary Key)
Name varchar(128)

So each location can be tagged with multiple tagwords, and each tagword can be tagged to multiple locations.

What I want to do is select only Locations which are tagged with all of the tag names supplied . For example:

I want all locations which are tagged with both "trees" and "swings". Location "Park" should be selected, but location "Forest" should not.

Any insight would be appreciated. Thanks!

Answer 1

There are two ways to do this. I prefer the first way, which is to self-join for each tag:

SELECT l.*
FROM Locations l
JOIN LocationsTagsAssoc a1 ON a1.LocationID = l.ID
JOIN Tags t1 ON a1.TagID = t1.ID AND t1.Name = ?
JOIN LocationsTagsAssoc a2 ON a2.LocationID = l.ID
JOIN Tags t2 ON a2.TagID = t2.ID AND t2.Name = ?
JOIN LocationsTagsAssoc a3 ON a3.LocationID = l.ID
JOIN Tags t3 ON a3.TagID = t3.ID AND t3.Name = ?;

The other way also works, but using GROUP BY in MySQL tends to incur a temporary table and performance is slow:

SELECT l.*
FROM Locations l
JOIN LocationsTagsAssoc a ON a.LocationID = l.ID
JOIN Tags t ON a.TagID = t.ID
WHERE t.Name IN (?, ?, ?)
GROUP BY l.ID
HAVING COUNT(*) = 3;

Answer 2

You need locations where there doesn't exist a given tag that doesn't appear in the LocationsTagsAssoc table with the location.

You can specify the given tags with IN () as in the following, or by joining onto another table containing them.

Ie

SELECT l.*
FROM Locations AS l
WHERE NOT EXISTS (
    SELECT NULL FROM Tags AS t
    WHERE NOT EXISTS (
        SELECT NULL FROM LocationsTagsAssoc AS lt
        WHERE lt.LocationId = l.ID
            AND lt.TagID = t.ID
    )
        AND t.ID IN (1, 2, 3,...)
)