如何从dll调用函数？

Question

How could I call a function from a DLL?

I tried to declare a void pointer and to store in it the result of GetProcAddress... but didn't work. I also wanted to declare an unsigned long int (I saw it somewhere on the internet), but then I didn't know how to continue on. :D

So, would anybody mind giving me a hand?

Answer 1

Try for something like this.

typedef int (*PFuncMethods)( int args );

hDLL  = LoadLibrary(L"your.dll");
if( !m_hDLL )
  return;

methods = (PFuncMethods)GetProcAddress(hDLL,"methods");
if ( !(methods) ) {
  FreeLibrary(hDLL);
  hDLL = NULL;
  methods = NULL;
  return;
} 

if( methods(1) == 0) ...

the method name is where you might be stuck aswell. C++ has name mangling for overloading (even if it's not overloaded) and that depends on the compiler. You can either work out the mangled name or turn off mangling for the function by using extern "C" . You might use a tool like depends.exe to see all the functions with exact name you would have to use.

It is much easier to statically link to the DLL using the (import)lib file in windows.

Answer 2

您必须创建一个函数指针而不是一个空指针，并将结果存储在GetProcAddress那个函数指针中。

Answer 3

You need to have exact function signature, and to cast the pointer properly.

For exmaple, if this is a function receiving int and returning void:

typedef void (*funcptr)(int);
funcptr func = (funcptr)(void*)GetProcAddress(....)
func(17);

Note1: If you confuse the signature, very bad things can happen. Note2: you also need to know the calling convention used (cdecl, stdcall, etc..)

If it's your DLL, better consider making an import library instead.