正则表达式以提取HREFS
[英]Regular Expression to extract HREFS
问题描述
I'm looking for a regular expression that can extract the href from this: 
我正在寻找可以从中提取href的正则表达式：
<a href="/tr/blog.php?post=3593&user=930">
There are hundreds of links on the page so I need to extract only those that contain 页面上有数百个链接，因此我只需要提取包含以下内容的链接
/tr/blog.php
So in the end I should be left with a list of links that start in /tr/blog 所以最后我应该留下以/ tr / blog开头的链接列表
Thanks for any help. 谢谢你的帮助。 It's really puzzling me. 这真的让我感到困惑。
This is the RegEx I am currently using, but it matches all. 这是我当前正在使用的RegEx，但它与所有匹配。
/href\s*=\s*\"*[^\">]*/ig;
3 个解决方案
解决方案1
2 2010-06-13 17:02:39
您可以尝试使用href=\\"(/tr/blog.php[^"]*)\\" （将捕获到第1组），但是通常不应该使用regex来解析HTML 。
解决方案2
0 2013-08-09 21:40:45
This is a bit late, but now that it's the future, you don't even need the regular expression: 这有点晚了，但是现在已经是将来，您甚至不需要正则表达式：
document.querySelectorAll("a[href*='/tr/blog.php']") will give you the links that contain that string, or you can find those that begin with that string document.querySelectorAll("[href^='/tr/blog.php']") . document.querySelectorAll("a[href*='/tr/blog.php']")将为您提供包含该字符串的链接，或者您可以找到以该字符串开头的链接document.querySelectorAll("[href^='/tr/blog.php']") 。
解决方案3
0 2010-06-13 22:26:40
<body> <a href="/tr/blog.php?lol">fslk</a>
<script>
var anchors = document.getElementsByTagName('a'), captured = [];
for ( var i = 0, l = anchors.length, href, r = /tr\/blog\.php/; i<l; ++i ) {
href = this.href;
if ( r.test( href ) ) {
captured.push( this )
}
}
// do what u want with captured links
for ( var l = captured.length; l--; ) {
alert( captured[l].href )
}
</script>
</body>
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