[英]simple javascript regex question
How can I match the following pattern? 如何匹配以下模式?
"anything123.anythingelse" “任何东西123.anythingelse”
Alphanum of any length, with exactly 1 "." 任何长度的Alphanum,正好为1“。” in the middle, and then alphanum of any length?
在中间,然后是任意长度的字母数字?
Thanks. 谢谢。
That would then be /[a-z0-9]+\\.[a-z0-9]+/i
. 那将是
/[a-z0-9]+\\.[a-z0-9]+/i
。 The /i
is the case insensitive modifier. /i
是不区分大小写的修饰符。
var match = /[a-z0-9]+\.[a-z0-9]+/i.test(string);
alert(match); // true or false.
If you can allow underscores, this can be done shorter: /\\w+\\.\\w+/
. 如果可以允许使用下划线,则可以将其缩短:/
/\\w+\\.\\w+/
. /\\w+\\.\\w+/
。 The \\w
is the same as [a-zA-Z0-9_]
. \\w
与[a-zA-Z0-9_]
。
See also : http://www.regular-expressions.info 另请参阅 : http : //www.regular-expressions.info
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