[英]jquery How to select the 1st cell of each table row
I have a table like this: 我有这样一张桌子:
<table id="myTable">
<tr><td>1sta</td><td>2nd</td></tr>
<tr><td>1stb</td><td>2nd</td></tr>
<tr><td>1stc</td><td>2nd</td></tr>
<tr><td>1std</td><td>2nd</td></tr>
</table>
Using jQuery How do I select the 1st <td>
element in each row of "myTable"? 使用jQuery如何在“myTable”的每一行中选择第一个
<td>
元素?
The first-child
selector grabs each td
that is the first child of its parent (the tr
in this case). first-child
选择器抓取每个td
,它是其父级的第一个子级(在本例中为tr
)。
$('#myTable td:first-child');
http://api.jquery.com/first-child-selector/ http://api.jquery.com/first-child-selector/
Use this selector '#myTable td:first-child'
. 使用此选择器
'#myTable td:first-child'
。
That will select the first td
for every tr
. 这将为每个
tr
选择第一个td
。 Avoid the temptation to use :first
instead of :first-child
. 避免使用的诱惑
:first
而不是:first-child
。 :first
will only select a single element. :first
只选择一个元素。 In this case it would be the first cell of the first row. 在这种情况下,它将是第一行的第一个单元格。
http://api.jquery.com/first-child-selector/ http://api.jquery.com/first-child-selector/
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