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使用xslt从特定xml元素中排除属性

[英]Exclude attribute from a specific xml element using xslt

I am new in xslt. 我是xslt的新手。 I have the following problem. 我有以下问题。 I need within an xml, to remove a specific attribute ( theAttribute in the example) from a specific element (eg div ). 我需要在xml中删除特定元素(例如div )中的特定属性( theAttribute中的theAttribute )。 ie

<html>
   <head>...</head>
   <body>
      <div id="qaz" theAtribute="44">
      </div>
      <div id ="ddd" theAtribute="4">
         <div id= "ggg" theAtribute="9">
         </div>
      </div>
      <font theAttribute="foo" />
   </body>
</html>

to become 成为

<html>
   <head>...</head>
   <body>
      <div id="qaz">
      </div>
      <div id ="ddd">
         <div id= "ggg">
         </div>
      </div>
      <font theAttribute="foo" />
   </body>
</html>

Where attribute theAtribute has been removed. where属性theAtribute已被删除。 I found this, http://www.biglist.com/lists/xsl-list/archives/200404/msg00668.html based on which i made attempts to find the proper solution. 我找到了这个, http://www.biglist.com/lists/xsl-list/archives/200404/msg00668.html ,我试图找到合适的解决方案。

ie <xsl:template match="@theAtribute" /> <xsl:template match="@theAtribute" />

Which removed it from the whole document... and others like match, if choose, etc. Nothing worked.. :-( can you please help me on this? it sound trivial to me, but with xslt, i cannot cope at all... 从整个文件中删除它...和其他像匹配,如果选择等等没有什么工作.. :-(你能帮我这个吗?这对我来说听起来微不足道,但是对于xslt,我根本无法应付...

Thank you all in advance 谢谢大家

What is not working? 什么不起作用? Do you want the same content, just without the @theAtribute ? 你想要相同的内容,只是没有@theAtribute

If so, make sure your stylesheet has the empty template for @theAtribute , but also has an identity template that copies everything else into the output: 如果是这样,请确保样式表具有@theAtribute的空模板,但也有一个标识模板,可将其他所有内容复制到输出中:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <!--empty template suppresses this attribute-->
    <xsl:template match="@theAtribute" />
    <!--identity template copies everything forward by default-->
    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>
</xsl:stylesheet>

If you only want to suppress certain @theAtribute , then you can make the match criteria more specific. 如果您只想禁止某些@theAtribute ,则可以使匹配条件更具体。 For instance, if you only wanted to remove that attribute from the div who's @id="qaz" , then you could use this template: 例如,如果您只想从div@id="qaz"删除该属性,那么您可以使用此模板:

<xsl:template match="@theAtribute[../@id='qaz']" />

or this template: 或者这个模板:

<xsl:template match="*[@id='qaz']/@theAtribute" />

If you want to remove @theAttribute from all div elements, then change the match expression to: 如果要从所有div元素中删除@theAttribute ,请将匹配表达式更改为:

<xsl:template match="div/@theAtribute" />

inside the select, you can exclude (or include,) the attribute, using the name function. 在select中,您可以使用name函数排除(或包含)该属性。

For example, <xsl:copy-of select="@*[name(.)!='theAtribute']|node()" /> 例如, <xsl:copy-of select="@*[name(.)!='theAtribute']|node()" />

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"  
xmlns:xs="http://www.w3.org/2001/XMLSchema" >

        <xsl:output method="xml" encoding="UTF-8" indent="yes" />
        <xsl:param name="status"/>

        <!--If attribute is present change it -->
        <xsl:template match="@status" >
            <xsl:attribute name="status" select="$status"/>
        </xsl:template>
        <!-- If attribute is not present add it al last position -->
        <xsl:template match="row[ not( @status ) ]" >
            <xsl:copy>
                <xsl:apply-templates select="@*"/>
                <!-- put attribute in the last position -->
                <xsl:attribute name="status" select="$status"/>
                <xsl:apply-templates select="node()"/>
            </xsl:copy>
        </xsl:template>

        <!--identity template copies everything forward by default-->
        <xsl:template match="@*|node()">
            <xsl:copy>
                <xsl:apply-templates select="@*|node()"/>
            </xsl:copy>
        </xsl:template>

    </xsl:stylesheet>

I have a xml like: 我有一个像xml:

<row  attribute1="value" >some stuff</row> 

and I'm adding at end of list of attributes a status from an outside value. 我在属性列表的末尾添加了一个来自外部值的状态。

\\saxonee\\bin\\Transform.exe -xsl:my_script.xsl -s:rows.xml status="completed" \\ saxonee \\ bin \\ Transform.exe -xsl:my_script.xsl -s:rows.xml status =“completed”

<row current_run="2019-07-29 19:00" status="completed">

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