Java字节数组

Question

I have a HashSet of byte[] s and I would like to test whether a new byte[] is in that set. The problem is that Java seems to be testing whether the byte[] instances are the same rather than testing whether the actual values in the byte arrays are the same.

In other words, consider the following code:

public class Test
{
    public static void main(String[] args)
    {
        java.util.HashSet<byte[]> set=new java.util.HashSet<byte[]>();
        set.add(new String("abc").getBytes());
        System.out.println(set.contains(new String("abc").getBytes()));
    }
}

This code prints out false and I would like it to print out true . How should I go about doing this?

Answer 1

You can wrap each byte array using ByteBuffer.wrap , which will provide the right equals and hashCode behavior for you. Just be careful what methods you call on the ByteBuffer (that you don't modify the array or advance its pointer).

Answer 2

You could create a ByteArray class that wraps the byte arrays and tests for equality the way you want. Then you'd have a Set<ByteArray> .

Answer 3

Modern ( as of right now solution )

import com.google.common.collect.ImmutableSet;

import java.nio.ByteBuffer;
import java.util.Set;

import static com.google.common.base.Charsets.UTF_8;
import static java.nio.ByteBuffer.wrap;

public class Scratch
{
    public static void main(String[] args)
    {
        final Set<ByteBuffer> bbs = ImmutableSet.of(wrap("abc".getBytes(UTF_8)).asReadOnlyBuffer());
        System.out.println("bbs.contains(ByteBuffer.wrap(\"abc\".getBytes(Charsets.UTF_8))) = " + bbs.contains(wrap("abc".getBytes(UTF_8)).asReadOnlyBuffer()));
    }
}

NOTES:

You should never convert a String to a byte[] without providing a Charset the results become runtime dependant based on the default Charset which is usually not a good one and can change.

.asReadOnlyBuffer() is important!

Creates a new, read-only byte buffer that shares this buffer's content. The content of the new buffer will be that of this buffer. Changes to this buffer's content will be visible in the new buffer; the new buffer itself, however, will be read-only and will not allow the shared content to be modified.

The two buffers' position, limit, and mark values will be independent.

The new buffer's capacity, limit, position, and mark values will be identical to those of this buffer. If this buffer is itself read-only then this method behaves in exactly the same way as the duplicate method.

Answer 4

您可以定义自己的包装类，但最简单的方法是将数组“包装”到ArrayLists中并使用HashSet<ArrayList> 。

Answer 5

You can avoid wrappers and the stupid hashCode problem (hey, a standard thing like a byte[] doesn't have hashCode right?):

Use TreeSet instead of HashSet and provide a byte[] comparator at instantiation time:

  Set<byte[]> byteATreeSet = new TreeSet<byte[]>(new Comparator<byte[]>() {
    public int compare(byte[] left, byte[] right) {
    for (int i = 0, j = 0; i < left.length && j < right.length; i++, j++) {
        int a = (left[i] & 0xff);
        int b = (right[j] & 0xff);
        if (a != b) {
            return a - b;
        }
    }
    return left.length - right.length;
   }});

If you get a byte[] HashSet b from somewhere else, initialize your variable a before as TreeSet and then use a.addAll(b); This way, even if b contained duplicates, a does not.