[英]How to select records who match criteria defined in a join table?
I have this three tables: 我有这三个表:
products TABLE:
id:integer
name:string
features TABLE:
id:integer
name:string
features_products TABLE:
product_id:integer
feature_id:integer
The features_products TABLE
tells me which features have each product. features_products TABLE
告诉我每个产品具有哪些功能。 For example: 例如:
product_id feature_id
1 3
1 5
3 4
tells me the product 1 has features 3 and 5 and product 3 have feature 4, also, product 2 (if exists) doesn't have features. 告诉我产品1具有功能3和5,产品3具有功能4,并且产品2(如果存在)不具有功能。
My question is, how can I SELECT
all the products from the products TABLE wich have determinated features? 我的问题是,如何从具有确定功能的表中SELECT
所有产品? For example, SELECT products which have features 3 AND 5
, or SELECT products which have feature 2
例如, SELECT products which have features 3 AND 5
SELECT products which have feature 2
或SELECT products which have feature 2
To select all the product ids for products which have both features 3 and 5: 要选择同时具有功能3和功能5的产品的所有产品ID:
SELECT product_id
FROM features_products
WHERE feature_id IN (3, 5)
GROUP BY product_id
HAVING COUNT(*) = 2
This assumes that there is a uniqueness contraint on (product_id, feature_id). 假设在(product_id,feature_id)上存在唯一性约束。 If you want the entire row from the product table then use this in a subquery: 如果要从产品表中获取整行,请在子查询中使用它:
SELECT *
FROM products
WHERE product_id IN (
SELECT product_id
FROM features_products
WHERE feature_id IN (3, 5)
GROUP BY product_id
HAVING COUNT(*) = 2
)
Something similar to this: 类似于以下内容:
select * from product
where id in ( select product_id from feature_products where feature id in ( 1,3 ) )
swap out the (1,3) for the features you want to include. 将(1,3)换为要包括的功能。
You could do the following the join those tables and get the data you need: 您可以执行以下操作来联接这些表并获取所需的数据:
SELECT *
FROM products p JOIN features_products fp ON p.id = fp.product_id
JOIN features f ON f.id = fp.feature_id
WHERE f.id = 3 OR f.id = 5
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