[英]C++ removing from list while iterating over list
I have a std::list
of Bananas
, and I want to get rid of the bad ones. 我有一个std::list
Bananas
std::list
,我想摆脱坏的。 Is there any relatively simple way to perform the following pseudocode? 是否有任何相对简单的方法来执行以下伪代码?
foreach(Banana banana in bananaList)
{
if(banana.isBad()) bananaList.remove(banana);
}
(Making a transition from C# and Java to C++ has been a rocky road.) (从C#和Java转换到C ++是一条艰难的道路。)
bananaList.remove_if(std::mem_fun_ref(&Banana::isBad));
Note that you should probably be using std::vector
instead of std::list
though -- vector
performs better in 99.9% of cases, and it's easier to work with. 请注意,你可能应该使用std::vector
而不是std::list
尽管 - 在99.9%的情况下, vector
表现更好,并且它更容易使用。
EDIT: If you were using vectors, vectors don't have a remove_if member function, so you'd have to use the plain remove_if
in namespace std
: 编辑:如果你使用向量,向量没有remove_if成员函数,所以你必须使用命名空间std
的普通remove_if
:
bananaVector.erase(
std::remove_if(bananaVector.begin(), bananaVector.end(), std::mem_fun_ref(&Banana::isBad)),
bananaVector.end());
You'd typically do something like: 你通常会这样做:
list.erase(std::remove_if(list.begin(), list.end(), std::mem_fun(Banana::isBad)), list.end());
Edit: Thanks to remove_if
being implemented as a member function of std::list
, Billy ONeal's answer is probably the better way to do the job as described, though this would be easier to convert when/if you decide to use a vector, deque, etc., which, as already discussed in comments, is probably a good thing to do. 编辑:由于remove_if
被实现为std::list
的成员函数,Billy ONeal的回答可能是更好的方式来完成所描述的工作,尽管如果你决定使用vector,deque时这会更容易转换等等,正如评论中已经讨论的那样,这可能是一件好事。
You can use a homebrew code like 您可以使用自制程序代码
for(list<...>::iterator it=bananas.begin(); end=bananas.end(); it!=end;) {
if(... decide ...) {
it=bananas.erase(it);
} else
++it;
}
or, you can use the list::remove_if
method, or std::remove_if
function (which is usable with a vector
, too). 或者,您可以使用list::remove_if
方法或std::remove_if
函数(也可以使用vector
)。
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