[英]Get subclass name?
Is it possible to get the name of a subclass?是否可以获取子类的名称? For example:
例如:
class Foo:
def bar(self):
print type(self)
class SubFoo(Foo):
pass
SubFoo().bar()
will print: < type 'instance' >
将打印:
< type 'instance' >
I'm looking for a way to get "SubFoo"
.我正在寻找一种获取
"SubFoo"
的方法。
I know you can do isinstance
, but I don't know the name of the class a priori, so that doesn't work for me.我知道你可以做
isinstance
,但我不知道 class 先验的名字,所以这对我不起作用。
you can use 您可以使用
SubFoo().__class__.__name__
which might be off-topic, since it gives you a class name :) 这可能是偏离主题的,因为它给你一个类名:)
#!/usr/bin/python
class Foo(object):
def bar(self):
print type(self)
class SubFoo(Foo):
pass
SubFoo().bar()
Subclassing from object
gives you new-style classes (which are not so new any more - python 2.2!) Anytime you want to work with the self attribute a lot you will get a lot more for your buck if you subclass from object. 从
object
子类化为你提供了新式的类(不再那么新了 - python 2.2!)无论何时你想要使用self属性,如果从对象继承,你将获得更多的帮助。 Python's docs ... new style classes . Python的文档...... 新的样式类 。 Historically Python left the old-style way
Foo()
for backward compatibility. 从历史上看,Python为了向后兼容而离开旧式方式
Foo()
。 But, this was a long time ago. 但是,这是很久以前的事了。 There is not much reason anymore not to subclass from object.
没有太多理由不从对象继承。
It works a lot better when you use new-style classes. 使用新式类时,它的效果会更好。
class Foo(object):
....
SubFoo.__name__
和父母: [cls.__name__ for cls in SubFoo.__bases__]
Just a reminder that this issue doesn't exist in Python 3.x
and print(type(self))
will give the more informative <class '__main__.SubFoo'>
instead of bad old < type 'instance' >
.提醒一下,这个问题在
Python 3.x
中不存在, print(type(self))
将提供更多信息<class '__main__.SubFoo'>
而不是旧的< type 'instance' >
。
This is because object
is subclassed automatically in Python 3.x
, making every class a new-style
class.这是因为
object
在Python 3.x
中被自动子类化,使每个 class 成为new-style
class。
More discussion at What is the purpose of subclassing the class "object" in Python?更多讨论在What is the purpose of subclassing the class "object" in Python? .
.
Like others pointed out, to just get the subclass name do print(type(self).__name__)
.就像其他人指出的那样,只需获取子类名称即可
print(type(self).__name__)
。
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