如何使用lxml删除python中与xpath匹配的所有元素？

Question

So I have some XML like this: 所以我有一些像这样的XML：

<bar>
  <foo>Something</foo>
  <baz>
     <foo>Hello</foo>
     <zap>Another</zap>
  <baz>
<bar>

And I want to remove all the foo nodes. 我想删除所有foo节点。 Something like this doesn't work 像这样的东西不起作用

params = xml.xpath('//foo')
for n in params:
  xml.getroot().remove(n)

Giving 给予

ValueError: Element is not a child of this node.

What is a neat way to do this? 什么是一个巧妙的方法来做到这一点？

Answer 1

try: 尝试：

 for elem in xml.xpath( '//foo' ) :
      elem.getparent().remove(elem)

remove it from it's parent, not the root ( unless it IS a child of the root element ) 从它的父节点而不是根节点中删除它（除非它是根元素的子节点）