php - 获取关联数组的数字索引

Question

I have an associative array and I need to find the numeric position of a key. I could loop through the array manually to find it, but is there a better way build into PHP?

$a = array(
  'blue'   => 'nice',
  'car'    => 'fast',
  'number' => 'none'
);

// echo (find numeric index of $a['car']); // output: 1

Answer 1

echo array_search("car",array_keys($a));

Answer 2

$blue_keys = array_search("blue", array_keys($a));

http://php.net/manual/en/function.array-keys.php

Answer 3

function arrayValuePosition($value, $array)
{
    return array_search($value, array_keys($array));
}

Answer 4

  $a = array(
      'blue' => 'nice',
      'car' => 'fast',
      'number' => 'none'
  );  
var_dump(array_search('car', array_keys($a)));
var_dump(array_search('blue', array_keys($a)));
var_dump(array_search('number', array_keys($a)));

Answer 5

While Fosco's answer is not wrong there is a case to be considered with this one: mixed arrays. Imagine I have an array like this:

$a = array(
  "nice",
  "car" => "fast",
  "none"
);

Now, PHP allows this kind of syntax but it has one problem: if I run Fosco's code I get 0 which is wrong for me, but why this happens?
Because when doing comparisons between strings and integers PHP converts strings to integers (and this is kinda stupid in my opinion), so when array_search() searches for the index it stops at the first one because apparently ("car" == 0) is true .
Setting array_search() to strict mode won't solve the problem because then array_search("0", array_keys($a)) would return false even if an element with index 0 exists.
So my solution just converts all indexes from array_keys() to strings and then compares them correctly:

echo array_search("car", array_map("strval", array_keys($a)));

Prints 1 , which is correct.

EDIT:
As Shaun pointed out in the comment below, the same thing applies to the index value, if you happen to search for an int index like this:

$a = array(
  "foo" => "bar",
  "nice",
  "car" => "fast",
  "none"
);
$ind = 0;
echo array_search($ind, array_map("strval", array_keys($a)));

You will always get 0 , which is wrong, so the solution would be to cast the index (if you use a variable) to a string like this:

$ind = 0;
echo array_search((string)$ind, array_map("strval", array_keys($a)));

Answer 6

a solution i came up with... probably pretty inefficient in comparison tho Fosco's solution:

 protected function getFirstPosition(array$array, $content, $key = true) {

  $index = 0;
  if ($key) {
   foreach ($array as $key => $value) {
    if ($key == $content) {
     return $index;
    }
    $index++;
   }
  } else {
   foreach ($array as $key => $value) {
    if ($value == $content) {
     return $index;
    }
    $index++;
   }
  }
 }

Answer 7

All solutions based on array_keys don't work for mixed arrays. Solution is simple:

echo array_search($needle,array_keys($haystack), true);

From php.net: If the third parameter strict is set to TRUE then the array_search() function will search for identical elements in the haystack. This means it will also perform a strict type comparison of the needle in the haystack, and objects must be the same instance.