C ++：打印数组时意外获取十六进制

Question

I am declaring an array using new

int *a = NULL;
a = new int[10];

a[0] = 23;
a[1] = 43;
a[2] = 45;
a[3] = 76;
a[4] = 34;
a[5] = 85;
a[6] = 34;
a[7] = 97;
a[8] = 45;
a[9] = 22;

PrintElements(a, 10);

void PrintElements(int * array, int size){
    for (int i=0; i<size; i++) {
        cout << endl << array[i];
    }
}

Now when I print the values I am getting these values

17
2b
2d
4c
22
55
22
61
2d
16

Can somebody tell me what am I doing wrong...? On the other hand when I dont use new & initialize array without it everything works fine.

Answer 1

You may have written a std::hex to the cout at some point; that will remain in effect until overridden.

Answer 2

It doesnt have anything to do with the static or dynamic allocation of the array.

The numbers are printed as Hexadecimal values and not decimal values.

Answer 3

Try:

std::cout << dec << //all your stuff here

It's still set in hex mode.

Answer 4

17 2b 2d 4c 22 55 22 61 2d 16

These are obviously hexadecimal numbers. If you print them as decimals you get 23, 43, etc. IOW, exactly the numbers that you have put into the array. Some piece of your code executed prior to your PrintElements() apparently changes the formatting to output hexadecimal numbers.