[英]how to extract a single digit in a number using regexp
set phoneNumber 1234567890
this number single digit, i want divide this number into 123 456 7890 by using regexp. 这个数字个位数,我想通过使用正则表达式将此数字分为123 456 7890。 without using split function is it possible?
不使用拆分功能,这可能吗?
The following snippet: 以下代码段:
regexp {(\d{3})(\d{3})(\d{4})} "8144658695" -> areacode first second
puts "($areacode) $first-$second"
Prints ( as seen on ideone.com ): 打印( 如ideone.com所示 ):
(814) 465-8695
This uses capturing groups in the pattern and subMatchVar...
for Tcl regexp
这将在模式和
subMatchVar...
使用捕获组 subMatchVar...
用于Tcl正则regexp
The regex pattern is: 正则表达式模式为:
(\d{3})(\d{3})(\d{4})
\_____/\_____/\_____/
1 2 3
It has 3 capturing groups (…)
. 它具有3个捕获组
(…)
。 The \\d
is a shorthand for the digit character class. \\d
是数字字符类的简写。 The {3}
in this context is "exactly 3 repetition of". 在这种情况下,
{3}
是“的3个重复”。
my($number) = "8144658695";
$number =~ m/(\d\d\d)(\d\d\d)(\d\d\d\d)/;
my $num1 = $1;
my $num2 = $2;
my $num3 = $3;
print $num1 . "\n";
print $num2 . "\n";
print $num3 . "\n";
This is writen for Perl and works assuming the number is in the exact format you specified, hope this helps. 这是为Perl写的,并且在假定数字与您指定的格式完全相同的情况下可以正常工作,希望能有所帮助。
This site might help you with regex http://www.troubleshooters.com/codecorn/littperl/perlreg.htm 该网站可能会帮助您使用正则表达式http://www.troubleshooters.com/codecorn/littperl/perlreg.htm
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