python：获取没有小数位的数字

Question

a=123.45324

有没有只返回123的函数？

Answer 1

int will always truncate towards zero:

>>> a = 123.456
>>> int(a)
123
>>> a = 0.9999
>>> int(a)
0
>>> int(-1.5)
-1

The difference between int and math.floor is that math.floor returns the number as a float, and does not truncate towards zero.

Answer 2

Python 2.x:

import math
int( math.floor( a ) )

NB Due to complicated reasons involving the handling of floats, the int cast is safe.

Python 3.x:

import math
math.floor( a )

Answer 3

a = 123.45324
int(a)

Answer 4

You can use the math.trunc() function:

a=10.2345
print(math.trunc(a))

Answer 5

If you want both the decimal and non-decimal part:

def split_at_decimal(num):
    integer, decimal = (int(i) for i in str(num).split(".")) 
    return integer, decimal

And then:

>>> split_at_decimal(num=5.55)
(5, 55)