您如何使C ++创建一个表达式，该表达式使用编译时检查常量并声明变量？

Question

Here's an example setup… a macro or a template CHECKEXPR_RETURNVAL(EXPR,VAL) that checks that EXPR is TRUE while returning VAL.

This is useful in a variety of places -- like in this highly simplified example:

#define ISPOW2(VAL)           ((0!=VAL)&&(0==(VAL&(VAL-1))))
#define _ALIGNPOW2(VAL,ALIGN) ((VAL+(ALIGN-1))&(~(ALIGN-1)))

#define ALIGNPOW2(VAL,ALIGN)  CHECKEXPR_RETURNVAL( \
    ISPOW2(ALIGN) , _ALIGNPOW2(VAL,ALIGN) )

So, the difficulty is this: I want to do compile time checks if possible, and if the value is not a constant that is determinate at compile time, then do a runtime check.

Basically, the idea is to catch bad parameters as soon as possible; if you can catch a bad parameter at compile time that's better than finding out at run time. Also, the compile time version is required for constant initializers.

---

Here are my two (failed) attempts to make single version work in multiple places (as a constant array size, as an enum initializer, and in a function with variables). Unfortunately, they either work for the compile time only (constant initializer) or the runtime only -- I would like to figure out a version that will work for both.

// CHECKEXPR_RETURNVAL - version "A"
#define CTCHECK_EXPR(EXP)(CTCheckBool<EXP>::ExistsZeroIfTrue)
template <bool bExpression> struct CTCheckBool {};
template <> struct CTCheckBool<true> {enum{ExistsZeroIfTrue=0};};
// Note: Plus ("+") is used rather than comma operator because
// the comma operator can not be used for constant initializers
#define CHECKEXPR_RETURNVAL_A(EXP,VAL) (CTCHECK_EXPR(EXP) + (VAL))

// Test Out version "A" -- works only for Compile Time Constants
#define ALIGNPOW2_A(VAL,ALIGN)  CHECKEXPR_RETURNVAL_A( \
    ISPOW2(ALIGN) , _ALIGNPOW2(VAL,ALIGN) )

char AlignedVar_A[ALIGNPOW2_A(2,8)];
enum { AlignedVal_A = ALIGNPOW2_A(57,16) };

int TestAlignPow2_A(int val, int align)
    {return(ALIGNPOW2_A(val,align));}       // Compile Error


// CHECKEXPR_RETURNVAL - version "B"
template<typename T> T CHECKEXPR_RETURNVAL_B(bool bExpr,T val)
    { ASSERT(bExpr); return(val); }

// Test Out version "B" -- works only for Runtime Computed Values
#define ALIGNPOW2_B(VAL,ALIGN)  CHECKEXPR_RETURNVAL_B( \
    ISPOW2(ALIGN) , _ALIGNPOW2(VAL,ALIGN) )

char AlignedVar_B[ALIGNPOW2_B(2,8)];        // Compile Error
enum { AlignedVal_B = ALIGNPOW2_B(57,16) }; // Compile Error

int TestAlignPow2_B(int val, int align)
    {return(ALIGNPOW2_B(val,align));}

Unfortunately, neither version works for all three cases. Is there a code structure that will work for all the cases ?

Answer 1

似乎您真的会使用c ++ 0x constexpr函数...

Answer 2

Well... Not a complete answer, but I think you can derive what you want from this:

#include <stdio.h>

template <int I> struct S{
    static void doIt(){
        fprintf(stderr, "wow\n");
    }
};

template<> void S<0>::doIt(){
    fprintf(stderr, "oops\n");
}

#define EXPR(p) S<(int)((bool)(p))>::doIt()     

int main(int argc, char** argv){
    EXPR((5+2)==7);
    EXPR((5+2)==8);
    const int a = 58;
    EXPR(a==58);
    EXPR(58);
    return 0;
}

You can get a compiler error based on expression:

#include <stdio.h>

template <int I> struct S{
    static void doIt(){
        ssdfkjehiu //deliberately invalid code
        fprintf(stderr, "oops\n");
    }
};

template<> void S<1>::doIt(){
    fprintf(stderr, "wow\n");
}

#define EXPR(p) S<(int)((bool)(p))>::doIt() 



int main(int argc, char** argv){
    EXPR((5+2)==7);
    EXPR((5+2)==8);//uncomment it to make code compile
    const int a = 58;
    EXPR(a==58);
    EXPR(58);
    return 0;
}

But the line that causes error will be in a middle of a lengthy template error message. Example:

1.cpp(6) : error C2065: 'asdlfkjhasd' : undeclared identifier
        1.cpp(4) : while compiling class template member function 'void S<I>::doIt(void)'
        with
        [
            I=0
        ]
        1.cpp(19) : see reference to class template instantiation 'S<I>' being compiled
        with
        [
            I=0
        ]
1.cpp(6) : error C2146: syntax error : missing ';' before identifier 'fprintf'

As you see, error is caused by line 19, which is mentioned in the middle of the message. This is a bit inconvenient.

I cannot guarantee that both examples doesn't rely on some undefined C++ behavior.

Also, I think that the next code maintainer may not be happy about this...

PS I think you should also take a look at boost. If I remember correctly, it had quite a lot of "magic preprocessor macro" (loops, for example), so it is possible that it implemented something similar.

--edit--
Okay, what about this one?:

#include <stdio.h>
#include <string>

template <typename T> void a(T &i){
    fprintf(stderr, "variable\n");  
}

void a(const char* const i){
    fprintf(stderr, "constant\n");
}

void a(bool i){
    fprintf(stderr, "constant\n");
}

int main(int argc, char** argv){
    int i;
    float f;
    std::string s;
    const char* s1 = "b";
    a(3);
    a(3+2);
    a(1.0f);
    a('a');
    a("b");
    a(i);
    a(f);
    a(s);
    a(s1);
    return 0;
}