[英]C++: Inheritance and Operator Overloading
I have two structs: 我有两个结构:
template <typename T>
struct Odp
{
T m_t;
T operator=(const T rhs)
{
return m_t = rhs;
}
};
struct Ftw : public Odp<int>
{
bool operator==(const Ftw& rhs)
{
return m_t == rhs.m_t;
}
};
I would like the following to compile: 我想要以下编译:
int main()
{
Odp<int> odp;
odp = 2;
Ftw f;
f = 2; // C2679: no operator could be found
}
Is there any way to make this work, or must I define the operator in Ftw
as well? 有没有办法让这项工作,或者我必须在Ftw
定义运算符?
The problem is that the compiler usually creates an operator=
for you (unless you provide one), and this operator=
hides the inherited one. 问题是编译器通常会为您创建一个operator=
(除非您提供一个),并且此operator=
隐藏继承的operator=
。 You can overrule this by using-declaration: 您可以通过using声明来否决它:
struct Ftw : public Odp<int>
{
using Odp<int>::operator=;
bool operator==(const Ftw& rhs)
{
return m_t == rhs.m_t;
}
};
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