[英]Check if jQuery method exists
Is it possible? 可能吗? No matter how, in Javascript or jQuery.
无论如何,在Javascript或jQuery中。
For example: $.isFunction($.isFunction());
例如:
$.isFunction($.isFunction());
Upd: But how to check method of a jQuery plugin? Upd:但是如何检查jQuery插件的方法? Sometimes it not ready at the moment of it call and generates error.
有时它在调用时没有准备好并产生错误。 Example:
$.isFunction($().jqGrid.format)
示例:
$.isFunction($().jqGrid.format)
To pass a function to another function, leave the ()
off: 要将函数传递给另一个函数,请关闭
()
:
$.isFunction($.isFunction); // true!
When you write ()
you are calling the function, and using the result it returns. 当你写
()
你正在调用该函数,并使用它返回的结果。 $.isFunction()
with no argument returns false
(because undefined
isn't a function), so you are saying $.isFunction(false)
, which is, naturally, also false
. 没有参数的
$.isFunction()
返回false
(因为undefined
不是函数),所以你说$.isFunction(false)
,当然也是false
。
I wouldn't bother using isFunction
merely to check for the existence of something, unless you suspect that someone might have assigned a non-function value to it for some reason. 我不
isFunction
只使用isFunction
来检查某些东西的存在,除非你怀疑有人可能因某种原因为它分配了一个非函数值。 For pure existence-checking, use the in
operator: 对于纯存在检查,请使用
in
运算符:
if ('isFunction' in $) { ...
Yes, 是,
jQuery.fn.exists = function(){return jQuery(this).length>0;}
if ($(selector).exists()) {
// code........
}
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