C＃：将数据添加到字典

Question

I have a list like

List<string> TempList = new List<string> { "[66,X,X]", "[67,X,2]", "[x,x,x]" };

I need to add data to the dictionary from the above list

Dictionary<int, int> Dict = new Dictionary<int, int>();

so the Dict should contain

Key --> 66 value --> 67

i need to take 66(first value) from first string([66,X,X]) and 67(first value) from second string( [67,X,X]) and add it as a key value pair into the dictionary.

Now i'm following string replacing and looping methodology to do this .

Is there any way to do this in LINQ or Regular expression.

Answer 1

After your comment that you're starting from a list of lists, I understood what you were after. I'm reusing Jaroslav's 'GetNumber' function here. Wrote my sample with array of array of string, but should work just the same. The code below will throw if you have duplicate keys, which I presume is what you want if you're using a dictionary.

        var input = new []
                        {
                            new [] { "[66,X,X]", "[67,X,2]", "[x,x,x]" },
                            new [] { "[5,X,X]", "[8,X,2]", "[x,x,x]" }
                        };

        var query = from l in input
                    select new 
                    {
                     Key = GetNumber(l.ElementAt(0)), 
                     Value = GetNumber(l.ElementAt(1))
                     };

        var dictionary = query.ToDictionary(x => x.Key, x => x.Value);

Answer 2

Here is an example using both string.Split() and a Regex:

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            List<string> data = new List<string>() { "[66,X,X]", "[67,X,2]", "[x,x,x]" };
            addToDict(data);

            Console.ReadKey();
        }

        private static void addToDict(List<string> items)
        {
            string key = items[0].Split('[', ',')[1];
            string val = items[1].Split('[', ',')[1];

            string pattern = @"(?:^\[)(\d+)";
            Match m = Regex.Match(items[0], pattern);
            key = m.Groups[1].Value;
            m = Regex.Match(items[1], pattern);
            val = m.Groups[1].Value;

            _dict.Add(key, val);
        }

        static Dictionary<string, string> _dict = new Dictionary<string, string>();
    }
}

i suspect that your example is quite contrived though, so there may be a better solution especially if you need to process large numbers of strings into key/value pairs (i deliberately hardcoded index values because your example was quite simple and i didn't want to over complicate the answer). If the input data is consistent in format then you can make assumptions like using fixed indexes, but if there is a possibility of some variance then there may need to be more code to check the validity of it.

Answer 3

You can use a regular expression to extract the value from each item in the list, and if you want, use LINQ to select out two lists and zip them together (in C# 4.0):

var regex      = new Regex(@"\d+");
var allValues  = TempList.Select(x =>int.Parse(regex.Match(x).Value));
var dictKeys   = allValues.Where((x,index)=> index % 2 == 0); //even-numbered 
var dictValues = allValues.Where((x,index)=> index % 2 > 0); //odd numbered 
var dict       = dictKeys.Zip(dictValues, (key,value) => new{key,value})
                         .ToDictionary(x=>x.key,x=>x.value);

If you're using C# 3.5, you can use Eric Lippert's implementation of Zip() .

Answer 4

IF I understand correctly: you want to create linked nodes like 66 -> 67, 67 -> 68, ... n -> n+1 ?

I would not use LINQ:

private static int GetNumber(string s)
{
    int endPos = s.IndexOf(',');
    return Int32.Parse(s.Substring(1, endPos-1));
}

And in code:

int first, second;    
for (int i = 1; i < TempList.Count; i++)
{
    first = GetNumber(TempList[i - 1]);
    second = GetNumber(TempList[i]);

    Dict.Add(first, second);
}

You should also perform checking, etc.
The sample assumes a list with at least 2 items.

Answer 5

List<List<string>> source = GetSource();

Dictionary<int, int> result = source.ToDictionary(
  tempList => GetNumber(tempList[0]),
  tempList => GetNumber(tempList[1])
);