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如何在Android中打开端口?

[英]How to open port in Android?

How can I open a specific port in android? 如何在android中打开特定端口?

I have a server socket but the connection is rejected because the port is closed. 我有一个服务器套接字,但由于端口已关闭,所以连接被拒绝。

try {
   ServerSocket server = new ServerSocket(2021);
   Socket client = server.accept(); 
} catch (Exception e) {
   // TODO Auto-generated catch block
   a = false;
   e.printStackTrace(); 
} 

If you still havn't got it to work, I would suggest that you create an inner class that extends Thread to replace that whole new Thread() { ... }.start() statement (I have always had trouble getting those to work exactly right when I try to declare an instance field, I just stick with creating/overriding methods in that kind of statement). 如果您仍然无法使用它,我建议您创建一个扩展Thread的内部类,以替换整个new Thread() { ... }.start()语句(我一直很难将它们转换为当我尝试声明实例字段时,它的工作完全正确,我只是坚持使用这种声明来创建/覆盖方法。 I would make the inner class, say ClientAnsweringThread , have a constructor that takes in the Socket ( client ) as a parameter and then calls ProcessClientRequest(_client); 我将使内部类(例如ClientAnsweringThread )具有一个将Socket( client )作为参数,然后调用ProcessClientRequest(_client); in the run() method as you already have. 就像在run()方法中一样。

It looks that you are just missing a loop around the accept() call so you can accept multiple connections. 看来您只是在accept()调用周围缺少了一个循环,所以您可以接受多个连接。 Something like this: 像这样:

ServerSocket server = new ServerSocket( port );

while ( true )
{
    Socket client = server.accept();
    ProcessClientRequest( client );
}

To illustrate what I meant in my comment: 为了说明我在评论中的意思:

ServerSocket server = new ServerSocket( port );
while ( true )
{
    Socket client = server.accept();
    new Thread () { 
        final Socket _client = client;
        // This stuff runs in a separate thread all by itself
        public void run () {
            ProcessClientRequest(_client);
        }
    }.start();
}

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