Python：如何改变（最后）元组的元素？

Question

The question is a bit misleading, because a tuple is immutable . What I want is:

Having a tuple a = (1, 2, 3, 4) get a tuple b that is exactly like a except for the last argument which is, say, twice the last element of a .

=> b == (1, 2, 3, 8)

Answer 1

b = a[:-1] + (a[-1]*2,)

What I'm doing here is concatenation of two tuples, the first containing everything but the last element, and a new tuple containing the mutation of the final element. The result is a new tuple containing what you want.

Note that for + to return a tuple, both operands must be a tuple.

Answer 2

I would do something like:

b=list(a)
b[-1]*=2
b=tuple(b)

Answer 3

Here's one way of doing it:

>>> a = (1, 2, 3, 4)
>>> b = a[:-1] + (a[-1]*2, )
>>> a
(1, 2, 3, 4)
>>> b
(1, 2, 3, 8)

So what happens on the second line? a[:-1] means all of a except the last element. a[-1] is the last element, and we multiply it by two. The (a[-1]*2, ) turns the result into a tuple, and the sliced tuple is concatenated with it using the + operator. The result is put in b.

You can probably fit this to your specific case.