Ruby - 覆盖def方法

Question

How can I overwrite the def method? But it's strange, cause I don't know from where the def method is defined. It's not Module, not Object, not BasicObject (of Ruby 1.9). And def.class don't say nothing ;)

I would like to use something like:

sub_def hello
  puts "Hello!"
  super
end

def hello
  puts "cruel world."
end

# ...and maybe it could print:
# => "Hello!"
# => "cruel world."

Many thanks, for any ideas.

Answer 1

Who told you def is a method? It's not. It's a keyword, like class , if , end , etc. So you cannot overwrite it, unless you want to write your own ruby interpreter.

Answer 2

You could use alias_method.

alias_method :orig_hello, :hello
def hello
  puts "Hello!"
  orig_hello
end

Answer 3

You can use blocks to do some similar things like this:

def hello
  puts "Hello"
  yield if block_given?
end

hello do
 puts "cruel world"
end

Answer 4

As others have said, def isn't a method, it's a keyword. You can't "override" it. You can, however, define a method called "def" via Ruby metaprogramming magic:

define_method :def do
  puts "this is a bad idea"
end

This still won't override the def keyword, but you can call your new method with method(:def).call .

So, there you (sort of) have it.

Note: I have no idea why you'd ever want to define a method called def . Don't do it.