[英]Elegant way to create a dictionary of pairs, from a list of tuples?
I have defined a tuple thus: (slot, gameid, bitrate) 我已经定义了一个元组:( slot,gameid,bitrate)
and created a list of them called myListOfTuples
. 并创建了一个名为
myListOfTuples
的列表。 In this list might be tuples containing the same gameid
. 在此列表中可能是包含相同
gameid
元组。
Eg the list can look like: 例如,列表可能如下所示:
[
(1, "Solitaire", 1000 ),
(2, "Diner Dash", 22322 ),
(3, "Solitaire", 0 ),
(4, "Super Mario Kart", 854564 ),
... and so on.
]
From this list, I need to create a dictionary of pairs - ( gameId
, bitrate
), where the bitrate
for that gameId
is the first one that I came across for that particular gameId
in myListOfTuples
. 从这个列表中,我需要创建一个对的字典 - (
gameId
, bitrate
),其中gameId
的bitrate
是我在gameId
中myListOfTuples
的第一个特定myListOfTuples
。
Eg From the above example - the dictionary of pairs would contain only one pair with gameId
"Solitaire" : ("Solitaire", 1000 )
because 1000 is the first bitrate found. 例如,从上面的例子中 - 对的字典只包含一对
gameId
“Solitaire”:( ("Solitaire", 1000 )
因为1000是第一个找到的比特率。
NB. NB。 I can create a set of unique games with this:
我可以创建一组独特的游戏:
uniqueGames = set( (e[1] for e in myListOfTuples ) )
For python2.6 对于python2.6
dict(x[1:] for x in reversed(myListOfTuples))
If you have Python2.7 or 3.1, you can use katrielalex's answer 如果你有Python2.7或3.1,你可以使用katrielalex的答案
{ gameId: bitrate for _, gameId, bitrate in reversed( myListOfTuples ) }.items( )
(This is a view, not a set. It has setlike operations, but if you need a set, cast it to one.) (这是一个视图,而不是一个集合。它具有setlike操作,但如果你需要一个集合,则将其转换为一个。)
Are you sure you want a set, not a dictionary of gameId: bitrate
? 你确定你想要一套,而不是
gameId: bitrate
字典gameId: bitrate
? The latter seems to me to be a more natural data structure for this problem. 在我看来,后者对于这个问题来说是更自然的数据结构。
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