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字符串拆分ASP.NET / C#

[英]String Split ASP.NET /C#

I am processing CSV File 我正在处理CSV文件

Say

ABC|06|001
PPP|06|001

I am running LINQ to split the CSV 我正在运行LINQ来拆分CSV

var path = Server.MapPath("~/App_Data/CSV.txt");
var _collectCSGData = from line in File.ReadAllLines(path)
                      let parts = line.Split('|')
                       select new { ID = parts[0],Assignment=parts[1]};

How to get the last item of each line ? 如何获得每行的最后一项?

(ie) (即)

001
001
from line in File.ReadAllLines(path)
select line.Split('|').LastOrDefault()

Something like: 就像是:

parts[parts.length -1]

should do the trick. 应该做的伎俩。

var _collectCSGData = from line in File.ReadAllLines(path) 
                      let parts = line.Split('|') 
                      let assignment = parts[parts.length - 1]
                       select assignment;

This should work, if you need to massage data, let is your friend. 这应该工作,如果你需要按摩数据, let你的朋友。

UPDATE: 更新:

Since parts may be empty you can have: 由于零件可能是空的,您可以:

let assignment = parts.length > 0 ? parts[parts.length - 1] : String.Empty

If you know it's the third part, how about adding to your anonymous constructor: 如果您知道这是第三部分,那么如何添加到您的匿名构造函数:

var _collectCSGData = from line in File.ReadAllLines(path)
                      let parts = line.Split('|');
                      select new 
                         {ID = parts[0], Assignment = parts[1], Data = parts[2]};

Or, if it's just "The last Item no matter how many items" 或者,如果它只是“最后一项无论多少项”

var _collectCSGData = from line in File.ReadAllLines(path)
                      let parts = line.Split('|');
                      select new 
                        {ID = parts[0], Assignment = parts[1], Data = parts[part.length-1]};

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