类型约束中的通用

Question

I'm struggling with some generics. The following is my setup:

interface I<T> { }

[...]
void Add<T>(T obj) where T : I<??> { }

How can I ensure that T in the Add method implements I ?

Answer 1

The following signature will allow Add to take any T that implements I<> with any type parameters.

void Add<T,S>(T obj) where T : I<S> {
}

The downside of using this method signature is that type inference doesn't kick in and you have to specify all the type parameters, which looks downright silly:

blah.Add<I<int>, int>(iInstance);

A much simpler approach is to use the below signature:

void Add<T>(I<T> obj) {
}

Answer 2

您还需要传递T参数来添加。

void Add<TI, TAny>(TI obj) where TI : I<TAny>