JSF 中的递归（c:forEach 与 ui:repeat）

Question

I am trying to build a navigation tree via recursion in JSF.我正在尝试通过 JSF 中的递归构建导航树。 I have defined a navigationNode component as:我已经定义了一个navigationNode组件：

<composite:interface>
    <composite:attribute name="node" />
</composite:interface>

<composite:implementation>
<ul>
    <ui:repeat value="#{navigationTreeBean.getChildrenForNode(cc.attrs.node)}" var="child">
        <li><navigation:navigationNode node="#{child}" /></li>
    </ui:repeat>
</ul>
</composite:implementation>

My tree is declared as:我的树被声明为：

rootNode = new DefaultMutableTreeNode(new NodeData("Dashboard", "dashboard.xhtml"), true);
DefaultMutableTreeNode configurationsNode = new DefaultMutableTreeNode(new NodeData("Configurations", "configurations.xhtml"), true);
rootNode.add(configurationsNode);

I call component by:我通过以下方式调用组件：

<nav:navigationNode node="#{rootNode}" />

The problem is, this results in StackOverflowError .问题是，这会导致StackOverflowError 。

There are a few references to building recursion in JSF (for example, c:forEach vs ui:repeat in Facelets ).有一些关于在 JSF 中构建递归的参考资料（例如， c:forEach 与 ui:repeat in Facelets ）。 The common problem seems to be mixing the build-time and render-time components/tags.常见的问题似乎是混合构建时和渲染时组件/标签。 In my case:就我而言：

My composite component is actually a tag, which is executed when the tree is built我的复合组件其实就是一个标签，在树构建的时候执行
ui:repeat is an actual JSF component, which is evaluated when the tree is rendered ui:repeat 是一个实际的 JSF 组件，它在树被渲染时被评估

Is the child component navigation:navigationNode actually processed before the ui:repeat component?子组件navigation:navigationNode真的在ui:repeat组件之前处理？ If so, what object is it using for #{child} ?如果是这样，它用于#{child}对象是什么？ Is it null (doesn't seem so)?它是否为空（似乎并非如此）？ Is the problem here that the child component is actually created without even caring about the ui:repeat and so each time a new child component is created even though it is not necessarily wanted?这里的问题是实际上创建了子组件而不关心 ui:repeat 等每次创建一个新的子组件时，即使它不一定需要？

The c:forEach vs ui:repeat in Facelets article has a separate section for this (recursion). Facelets文章中的c:forEach 与 ui:repeat对此（递归）有一个单独的部分。 The suggestion is to to use c:forEach instead.建议使用c:forEach代替。 I tried this, however it is still giving me the same StackOverflowError , with different trace that I cannot make sense of.我试过这个，但是它仍然给我相同的StackOverflowError ，具有我无法理解的不同跟踪。

I know that we can also build components by extending UIComponent , but that approach (writing html in Java code) seems ugly.我知道我们也可以通过扩展UIComponent来构建组件，但是这种方法（用 Java 代码编写 html）看起来很丑陋。 I would rather use MVC style / templates.我宁愿使用 MVC 样式/模板。 However, if there are no other ways, do I have to implement this sort of recursion as UIComponent instead?但是，如果没有其他方法，我是否必须将这种递归实现为 UIComponent ？

Answer 1

JSF's built-in declarative tags are ill-suited for handling this sort of recursion. JSF 的内置声明性标签不适合处理这种递归。 JSF builds a stateful component tree that is persisted between requests. JSF 构建了一个在请求之间持久化的有状态组件树。 If the view is restored in a subsequent request, the view state may not reflect changes in the model.如果视图在后续请求中恢复，则视图状态可能不会反映模型中的更改。

I would favour an imperative approach.我赞成一种命令式的方法。 You have two options as I see it:在我看来，您有两个选择：

Use the binding attribute to bind a control (eg some form of panel) to a backing bean that provides the UIComponent instance and its children - you write code to instantiate the UIComponent and add whatever children you want.使用binding属性将控件（例如某种形式的面板）绑定到提供UIComponent实例及其子项的支持 bean - 您编写代码来实例化UIComponent并添加您想要的UIComponent项。 See the spec for the binding attribute contract.请参阅binding属性协定的规范。
Write a custom control, implementing some of: a UIComponent ;编写一个自定义控件，实现一些： UIComponent ； a Renderer ; Renderer ； a tag handler;标签处理程序； meta-data files (delete as appropriate - you do some or all of these depending on what you are doing and how and in which version of JSF).元数据文件（根据需要删除 - 您可以根据您正在做什么以及如何以及在哪个版本的 JSF 中执行其中的部分或全部操作）。

Perhaps another option is to pick up a 3rd party control that already does this.也许另一种选择是选择已经执行此操作的第 3 方控件。

UPDATE: If one is using the very useful OmniFaces library (you should if you don't already), there is the <o:tree> which has no html generation whatsoever but was specifically designed to support usecases like this.更新：如果有人正在使用非常有用的OmniFaces 库（如果你还没有，你应该使用），有<o:tree>它没有任何 html 生成，但专门设计用于支持这样的用例。

<o:tree value="#{bean.treeModel}" var="item" varNode="node">
    <o:treeNode>
        <ul>
            <o:treeNodeItem>
                <li>
                    #{node.index} #{item.someProperty}
                    <o:treeInsertChildren />
                </li>
            </o:treeNodeItem>
        </ul>
    </o:treeNode>
</o:tree>

EDIT:编辑：

Here's a model-driven approach that doesn't involve writing custom components or backing-bean-generated component trees.这是一种模型驱动的方法，它不涉及编写自定义组件或支持 bean 生成的组件树。 It's kind of ugly.有点丑。

The Facelets view: Facelets 视图：

<?xml version='1.0' encoding='UTF-8' ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
   "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml"
      xmlns:h="http://java.sun.com/jsf/html"
      xmlns:ui="http://java.sun.com/jsf/facelets">
  <h:head><title>Facelet Tree</title></h:head>
  <h:body>
    <ul>
      <ui:repeat value="#{tree.treeNodes}" var="node">
        <h:outputText rendered="#{node.firstChild}"
                value="&lt;ul&gt;" escape="false" />
        <li>
          <h:outputText value="#{node.value}" />
        </li>
        <ui:repeat rendered="#{node.lastChild and empty node.kids}"
            value="#{node.lastChildLineage}" var="ignore">
          <h:outputText
              value="&lt;/ul&gt;" escape="false" />
        </ui:repeat>
      </ui:repeat>
    </ul>
  </h:body>
</html>

The managed bean:托管 bean：

@javax.faces.bean.ManagedBean(name = "tree")
@javax.faces.bean.RequestScoped
public class Tree {
  private Node<String> root = new Node(null, "JSF Stuff");

  @PostConstruct
  public void initData() {
    root.getKids().add(new Node(root, "Chapter One"));
    root.getKids().add(new Node(root, "Chapter Two"));
    root.getKids().add(new Node(root, "Chapter Three"));
    Node<String> chapter2 = root.getKids().get(1);
    chapter2.getKids().add(new Node(chapter2, "Section A"));
    chapter2.getKids().add(new Node(chapter2, "Section B"));
  }

  public List<Node<String>> getTreeNodes() {
    return walk(new ArrayList<Node<String>>(), root);
  }

  private List<Node<String>> walk(List<Node<String>> list, Node<String> node) {
    list.add(node);
    for(Node<String> kid : node.getKids()) {
      walk(list, kid);
    }
    return list;
  }
}

A tree node:一个树节点：

public class Node<T> {
  private T value;
  private Node<T> parent;
  private LinkedList<Node<T>> kids = new LinkedList<>();

  public Node(Node<T> parent, T value) {
    this.parent = parent;
    this.value = value;
  }

  public List<Node<T>> getKids() {return kids;}
  public T getValue() { return value; }

  public boolean getHasParent() { return parent != null; }

  public boolean isFirstChild() {
    return parent != null && parent.kids.peekFirst() == this;
  }

  public boolean isLastChild() {
    return parent != null && parent.kids.peekLast() == this;
  }

  public List<Node> getLastChildLineage() {
    Node node = this;
    List<Node> lineage = new ArrayList<>();
    while(node.isLastChild()) {
        lineage.add(node);
        node = node.parent;
    }
    return lineage;
  }
}

Output:输出：

*  JSF Stuff
      o Chapter One
      o Chapter Two
            + Section A
            + Section B 
      o Chapter Three

I would still bite the bullet and write a custom tree control.我仍然会咬紧牙关写一个自定义的树控件。

Answer 2

I had a similar issue(StackOverflowException) while migrating our app from jsf 1.x to 2.x.在将我们的应用程序从 jsf 1.x 迁移到 2.x 时，我遇到了类似的问题（StackOverflowException）。 If you're using the c:forEach approach to jsf recursion, make sure you're using the new namespace for jstl core.如果您使用 c:forEach 方法进行 jsf 递归，请确保您使用的是新的 jstl 核心命名空间。 Use用

xmlns:c="http://java.sun.com/jsp/jstl/core"

instead of代替

xmlns:c="http://java.sun.com/jstl/core"

Here's the pattern we we're using, adapted to your scenario.这是我们正在使用的模式，适用于您的场景。

client.xhtml客户端.xhtml

<ui:include src="recursive.xhtml">
    <ui:param name="node" value="#{child}" />
</ui:include>

recursive.xhtml递归.xhtml

<ui:composition xmlns="http://www.w3.org/1999/xhtml"
    xmlns:ui="http://java.sun.com/jsf/facelets"
    xmlns:h="http://java.sun.com/jsf/html"
    xmlns:f="http://java.sun.com/jsf/core"
    xmlns:c="http://java.sun.com/jsp/jstl/core" >
    <ul>
        <c:forEach items="#{node.children}" var="child">
            <li>
                #{child.label}
                <ui:include src="recursive.xhtml">
                    <ui:param name="node" value="#{child}" />
                </ui:include>
            </li>
        </c:forEach>
    </ul>   
</ui:composition>

JSF 中的递归（c:forEach 与 ui:repeat）

问题描述

2 个解决方案

解决方案1
5 已采纳 2010-08-16 21:49:33

解决方案2
4 2013-03-07 18:23:05

JSF 中的递归（c:forEach 与 ui:repeat）

问题描述

2 个解决方案

解决方案1 5 已采纳 2010-08-16 21:49:33

解决方案2 4 2013-03-07 18:23:05

解决方案1
5 已采纳 2010-08-16 21:49:33

解决方案2
4 2013-03-07 18:23:05