在C ++中获得最小的NEGATIVE浮点值

Question

I was looking at std::numeric_limits<float>::min/max() but it appears 'min()' returns the smallest absolute value, not the lowest value. Is it safe to use

-std::numeric_limits<float>::max() , ie is float symmetric in min/max limits?

Answer 1

IEEE 754浮点数使用符号位进行签名（而不是二进制补码），所以如果您确定您的编译器/平台使用该表示（非常常见），那么您可以使用-std::numeric_limits<float>::max()你怀疑-std::numeric_limits<float>::max() 。

Answer 2

use std::numeric_limits::lowest()

static _Ty __CRTDECL lowest() _THROW0()
    {   // return most negative value
    return (-(max)());
    }

Answer 3

Yes, float is symmetric in minimum/maximum values.

If you're using the lowest representable value as an initial value in searching a list for its maximum value, consider using infinity instead.

std::numeric_limits<T>::has_infinity() will return true for any numeric type that has it and std::numeric_limits<T>::infinity() will return a value that always evaluates greater than any other non-NaN value for that type. This value can be negated and will evaluate less than anything else.