[英]How to find the depth of each node in std::map?
If I construct, my own binary tree, then I can find the depth of each node. 如果构造自己的二叉树,则可以找到每个节点的深度。 The sample code is as follows 示例代码如下
template<class datatype>
void binary_node<datatype>::printNodeWithDepth(int currentNodeDepth)
{
if ( left )
left->printNodeWithDepth(currentNodeDepth+1);
std::cout << value << " and the depth is " << currentNodeDepth << std::endl;
if ( right)
right->printNodeWithDepth(currentNodeDepth+1);
}
But wondering, since map is a b-tree, is it possible to write something similar to this for a std::map
? 但是想知道,由于map是b树,是否可以为std::map
编写与此类似的内容?
std::map
is not guaranteed to be a b-tree, it is just guaranteed to have at least as good runtime complexity. std::map
不保证是b树,只保证至少具有良好的运行时复杂度。 To open the door for other potential implementations, the interface does not include functions for inspecting this kind of implementation details. 为了为其他潜在的实现打开大门,该界面不包含用于检查此类实现细节的功能。 :) :)
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