[英]How to generate a random list of fixed length of values from given range?
How to generate a random (but unique and sorted) list of a fixed given length out of numbers of a given range in Python?如何从 Python 中给定范围的数字中生成固定给定长度的随机(但唯一且已排序)列表?
Something like that:类似的东西:
>>> list_length = 4
>>> values_range = [1, 30]
>>> random_list(list_length, values_range)
[1, 6, 17, 29]
>>> random_list(list_length, values_range)
[5, 6, 22, 24]
>>> random_list(3, [0, 11])
[0, 7, 10]
A random sample like this returns list of unique items of sequence.像这样的随机样本返回序列中唯一项的列表。 Don't confuse this with random integers in the range.不要将此与范围内的随机整数混淆。
>>> import random
>>> random.sample(range(30), 4)
[3, 1, 21, 19]
A combination of random.randrange and list comprehension would work. random.randrange和列表理解的组合会起作用。
import random
[random.randrange(1, 10) for _ in range(0, 4)]
import random
def simplest(list_length):
core_items = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
random.shuffle(core_items)
return core_items[0:list_length]
def full_random(list_length):
core_items = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
result = []
for i in range(list_length):
result.append(random.choice(core_items))
return result
You can achieve this using random.choices() if you want to sample with replacement.如果你想用替换采样,你可以使用 random.choices() 来实现。
>>> import random
>>> random.choices(range(15), k=3)
[24, 29, 17]
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