在python中合并排序

Question

basically I have a bunch of files containing domains. I've sorted each individual file based on its TLD using .sort(key=func_that_returns_tld)

now that I've done that I want to merge all the files and end up wtih one massive sorted file. I assume I need something like this:

open all files
read one line from each file into a list
sort list with .sort(key=func_that_returns_tld)
output that list to file
loop by reading next line

am I thinking about this right? any advice on how to accomplish this would be appreciated.

Answer 1

If your files are not very large, then simply read them all into memory (as S. Lott suggests). That would definitely be simplest.

However, you mention collation creates one "massive" file. If it's too massive to fit in memory, then perhaps use heapq.merge . It may be a little harder to set up, but it has the advantage of not requiring that all the iterables be pulled into memory at once.

import heapq
import contextlib

class Domain(object):
    def __init__(self,domain):
        self.domain=domain
    @property
    def tld(self):
        # Put your function for calculating TLD here
        return self.domain.split('.',1)[0]
    def __lt__(self,other):
        return self.tld<=other.tld
    def __str__(self):
        return self.domain

class DomFile(file):
    def next(self):
        return Domain(file.next(self).strip())

filenames=('data1.txt','data2.txt')
with contextlib.nested(*(DomFile(filename,'r') for filename in filenames)) as fhs:
    for elt in heapq.merge(*fhs):
        print(elt)

with data1.txt:

google.com
stackoverflow.com
yahoo.com

and data2.txt:

standards.freedesktop.org
www.imagemagick.org

yields:

google.com
stackoverflow.com
standards.freedesktop.org
www.imagemagick.org
yahoo.com

Answer 2

Unless your file is incomprehensibly huge, it will fit into memory.

Your pseudo-code is hard to read. Please indent your pseudo-code correctly. The final "loop by reading next line" makes no sense.

Basically, it's this.

all_data= []
for f in list_of_files:
    with open(f,'r') as source:
        all_data.extend( source.readlines() )
all_data.sort(... whatever your keys are... )

You're done. You can write all_data to a file, or process it further or whatever you want to do with it.

Answer 3

另一个选择（同样，仅当您的所有数据都无法容纳到内存中时）是创建一个SQLite3数据库并在那里进行排序，然后将其写入文件。