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Init.d脚本挂起

[英]Init.d script hanging

I have an init.d script that looks like: 我有一个init.d脚本,看起来像:

#!/bin/bash
# chkconfig 345 85 60
# description: startup script for swapi
# processname: swapi

LDIR=/var/www/html/private/daemon
EXEC=swapi.php
PIDF=/var/run/swapi.pid
IEXE=/etc/init.d/swapi

### BEGIN INIT INFO
# Provides: swapi
# Required-Start: $local_fs
# Required-Stop:
# Default-Start: 3 4 5
# Default-Stop: 0 1 2 6
# Short-Description: startup script for swapi
# Description: startup script for swapi.php which processes actionq into switch
### END INIT INFO

if [ ! -f $LDIR/$EXEC ]
then
        echo "swapi was not found at $LDIR/$EXEC"
        exit
fi

case "$1" in
  start)
        if [ -f $PIDF ]
        then
                echo "swapi is currently running. Killing running process..."
                $IEXE stop
        fi
        $LDIR/$EXEC >> $LDIR/swapi.log & MYPID=$!
        echo $MYPID > $PIDF
        echo "swapi is now running."
        ;;
  stop)
        if [ -f $PIDF ]
        then
                echo "Stopping swapi."
                PID_2=`cat $PIDF`
                if [ ! -z "`ps -f -p $PID_2 | grep -v grep | grep 'swapi'`" ]
                then
                        kill -9 $PID_2
                fi
                rm -f $PIDF
        else
                echo "swapi is not running, cannot stop it. Aborting now..."
        fi
        ;;
  force-reload|restart)
        $0 stop
        $0 start
        ;;
  *)
        echo "Use: /etc/init.d/swapi {start|stop|restart|force-reload}"
        exit 1
esac

And then I have a keepalive cronjob that calls this if the pid goes down. 然后我有一个keepalive cronjob,如果pid下降,就会调用它。 Problem is that that keepalive script hangs whenever I run it like a cron job (ie. run-parts /var/www/html/private/fivemin), (the keepalive script being in /var/www/html/private/fivemin). 问题是每当我像cron作业一样运行keepalive脚本时就会挂起(即run-parts / var / www / html / private / fivemin),(keepalive脚本在/ var / www / html / private / fivemin中) 。

Is there something funky in my init.d script that I am missing? 在我的init.d脚本中是否有一些我缺少的东西?

I have been racking my brain on this problem for hours now! 我几个小时以来一直在讨论这个问题! I am on centos4 btw. 我顺便说一下。

Thanks for any help. 谢谢你的帮助。 -Eric -Eric

EDIT: 编辑:

The keepalive/cronjob script was simplified for testing to a simple: keepalive / cronjob脚本被简化为测试简单:

#!/usr/bin/php
<?

exec("/etc/init.d/swapi start");

?>

The strange this is the error output from swapi.php is put into /var/spool/mail like normal cron output except that I have all the output being dumped into the swapi.log in the init.d script? 奇怪的是这是从swapi.php输出的错误被放入/ var / spool / mail中,就像普通的cron输出一样,除了我将所有输出都转储到init.d脚本中的swapi.log中?

When I run keepalive.php from the cli (as root from /) it operates exactly as I would expect it to. 当我从cli运行keepalive.php(作为/的root)时,它的操作完全符合我的预期。

When keepalive runs ps aux | 当keepalive运行ps aux | grep php looks like: grep php看起来像:

root      4525  0.0  0.0  5416  584 ?        S    15:10   0:00 awk -v progname=/var/www/html/private/fivemin/keepalive.php progname {?????   print progname ":\n"?????   progname="";????       }????       { print; }
root      4527  0.7  1.4 65184 14264 ?       S    15:10   0:00 /usr/bin/php /var/www/html/private/daemon/swapi.php

And If I do a: 如果我这样做:

/etc/init.d/swapi stop

from the cli then both programs are no longer listed. 从cli开始,两个程序都不再列出。

Swapi ls -l looks like: Swapi ls -l看起来像:

-rwxr-xr-x  1 5500 5500 33148 Aug 29 15:07 swapi.php

Here is what the crontab looks like: 这是crontab的样子:

*/5 * * * * root run-parts /var/www/html/private/fivemin

Here is the first bit of swapi.php 这是swapi.php的第一个位

#!/usr/bin/php
<?
chdir(dirname( __FILE__ ));
include("../../config/db.php");
include("../../config/sql.php");
include("../../config/config.php");
include("config_local.php");
include("../../config/msg.php");

include("../../include/functions.php");

set_time_limit(0);
echo "starting @ ".date("Ymd.Gi")."...\n";
$actionstr  =   "";
while(TRUE){

I modified the init.d script and put init above the variable declarations, it did not make a difference. 我修改了init.d脚本并将init放在变量声明之上,它没有什么区别。

The answer was that bash was staying open because my init.d script was not redirecting the stderr output. 答案是bash保持打开状态,因为我的init.d脚本没有重定向stderr输出。 I have now changed it to 我现在把它改成了

$LDIR/$EXEC &> $LDIR/swapi.log & MYPID=$!

And it now functions perfectly. 它现在功能完美。

Thanks for the help everyone! 感谢大家的帮助!

When you run a command from cron , the environment is not the same as when it is run from the bash command line after logging in. I would suspect in this case that the sh is not able to understand swapi.php as a PHP command. 当您从cron运行命令时,环境与登录后从bash命令行运行时的环境不同。我怀疑在这种情况下sh不能将swapi.php理解为PHP命令。

Do a 做一个

which php

to see where your php binary is and add this to your init.d script 查看php二进制文件的位置并将其添加到init.d脚本中

PHP=/usr/bin/php 
...
$PHP $LDIR/$EXEC >> $LDIR/swapi.log & MYPID=$!

Probably not that important but you may want to redirect the output from the cron line 可能不那么重要,但您可能想要重定向cron行的输出

0 * * * * /path/to/script 2>&1 >> /dev/null

for instance. 例如。

Make sure your script has the correct execution permissions, the right owner, and the first lines should look like this: 确保您的脚本具有正确的执行权限,正确的所有者,并且第一行应如下所示:

#!/usr/bin/php
<?php

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