如何根据其值以升序打印出HashMap <String，String>的内容？

Question

I have this HashMap that I need to print out in ascending order according to the values contained in it ( not the keys ).

But the order when I print it out is seemingly random.

What's the best way to print it out in ascending value order ?

Map<String, String> codes = new HashMap<String, String>();

codes.put("A1", "Aania");
codes.put("X1", "Abatha");
codes.put("C1", "Acathan");
codes.put("S1", "Adreenas");

In other words, the example above should print out as this:

A1, Aania
X1, Abatha
C1, Acathan
S1, Adreenas

Answer 1

You aren't going to be able to do this from the HashMap class alone.

I would take the Map<String, String> codes , construct a reverse map of TreeMap<String, String> reversedMap where you map the values of the codes Map to the keys (this would require your original Map to have a one-to-one mapping from key-to-value). Since the TreeMap provides Iterators which returns entries in ascending key order, this will give you the value/key combination of the first map in the order (sorted by values) you desire.

Map<String, String> reversedMap = new TreeMap<String, String>(codes);

//then you just access the reversedMap however you like...
for (Map.Entry entry : reversedMap.entrySet()) {
    System.out.println(entry.getKey() + ", " + entry.getValue());
}

There are several collections libraries (commons-collections, Google Collections, etc) which have similar bidirectional Map implementations.

Answer 2

You'll need to make a list of the keys, sort them according to the corresponding values, then iterate over the sorted keys.

Map<String, String> map = getMyMap();
List<String> keys = new ArrayList<String>(map.keySet());
Collections.sort(keys, someComparator);
for (String key: keys) {
    System.out.println(key + ": " + map.get(key));
}

As for what to use for someComparator , here are some handy, generic Comparator-creating routines I often find useful. The first one sorts by the values according to their natural ordering, and the second allows you to specify any arbitrary Comparator to sort the values:

public static <K, V extends Comparable<? super V>>
        Comparator<K> mapValueComparator(final Map<K, V> map) {
    return new Comparator<K>() {
        public int compare(K key1, K key2) {
            return map.get(key1).compareTo(map.get(key2));
        }
    };
}

public static <K, V>
        Comparator<K> mapValueComparator(final Map<K, V> map,
                                         final Comparator<V> comparator) {
    return new Comparator<K>() {
        public int compare(K key1, K key2) {
            return comparator.compare(map.get(key1), map.get(key2));
        }
    };
}

Answer 3

It's time to add some lambdas:

codes.entrySet()
    .stream()
    .sorted(Comparator.comparing(Map.Entry::getValue))
    .forEach(System.out::println);

Answer 4

the for loop of for(Map.Entry entry: codes.entrySet() ) didn't work for me. Used Iterator instead.

Iterator<Map.Entry<String, String>> i = codes.entrySet().iterator(); 
while(i.hasNext()){
    String key = i.next().getKey();
    System.out.println(key+", "+codes.get(key));
}

Answer 5

you just need to use:

 Map<>.toString().replace("]","\n");

and replaces the ending square bracket of each key=value set with a new line.

Answer 6

Java 8

map.entrySet().stream().sorted(Map.Entry.comparingByValue()).forEach(System.out::println);

Answer 7

1. Create a TreeMap<String,String>
2. Add each of the HashMap entries with the value as the key.
3. iterate the TreeMap

If the values are nonunique, you would need a list in the second position.

Answer 8

You can use a list of the entry set rather than the key set and it is a more natural choice given you are sorting based on the value. This avoids a lot of unneeded lookups in the sorting and printing of the entries.

Map<String, String> map = ...
List<Map.Entry<String, String>> listOfEntries = new ArrayList<Map.Entry<String, String>>(map.entrySet());
Collections.sort(listOfEntries, new SortByValueComparator());
for(Map.Entry<String, String> entry: listOfEntries)
   System.out.println(entry);

static class SortByValueComparator implements Comparator<Map.Entry<String, String>> {
   public int compareTo(Map.Entry<String, String> e1, Map.Entry<String, String> e2) {
       return e1.getValue().compateTo(e2.getValue());
   }
}

Answer 9

the simplest and shortest code i think is this:

public void listPrinter(LinkedHashMap<String, String> caseList) {

    for(Entry entry:caseList.entrySet()) {
        System.out.println("K: \t"+entry.getKey()+", V: \t"+entry.getValue());
    }
}

Answer 10

The simplest solution would be to use a sorted map like TreeMap instead of HashMap. If you do not have control over the map construction, then the minimal solution would be to construct a sorted set of keys. You don't really need a new map.

Set<String> sortedKeys = new TreeSet<String>();
sortedKeys.addAll(codes.keySet());

for(String key: sortedKeys){
    println(key  + ":" + codes.get(key));
}

Answer 11

Try:

try
{
    int cnt= m.getSmartPhoneCount("HTC",true);      
    System.out.println("total count of HTC="+cnt);
}  
catch (NoSuchBrandSmartPhoneAvailableException e)
{
    // TODO Auto-generated catch 
    e.printStackTrace();
}

Answer 12

 SmartPhone[] sp=new SmartPhone[4];
 sp[0]=new SmartPhone(1,"HTC","desire","black",20000,10,true,true);
 sp[1]=new SmartPhone(2,"samsung","grand","black",5000,10,false,true);
 sp[2]=new SmartPhone(14,"google nexus","desire","black",2000,30,true,false);
 sp[3]=new SmartPhone(13,"HTC","desire","white",50000,40,false,false);

Answer 13

while (itr.hasNext()) {
    Vehicle vc=(Vehicle) itr.next();
    if(vc.getVehicleType().equalsIgnoreCase(s)) {
        count++;
    }
}