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如何使用带有类的模板

[英]How to have a Struct with template with a class

With this code (just a class of test): 使用此代码(只是一类测试):

typedef unsigned short UInt16;

template<class T>
class CClass
{
public:
    SValue* getNewSValue(void);
private:
    typedef struct {
        T *mValue;
        T *next;
        T *previous;
        UInt16 index;
    } SValue;
};

template<typename T>
SValue* CClass<T>::getNewSValue(void)
{
    return new SValue;
}

I have the following errors: 我有以下错误:

error C2143: syntax error : missing ';' 错误C2143:语法错误:缺少';' before '*' 在'*'之前

error C4430: missing type specifier - int assumed. 错误C4430:缺少类型说明符 - 假定为int。 Note: C++ does not support default-int 注意:C ++不支持default-int

Is it possible to use a Struct within a class? 是否可以在类中使用Struct? If I declare the struct out of the class the template doesn't see the template T . 如果我从类中声明结构,模板就看不到模板T

$9.2/2- The key is the below quote from the C++ Standard03 $ 9.2 / 2-关键是C ++ Standard03的以下引用

`A class is considered a completely-defined object type (3.9) (or complete type) at the closing } of the class-specifier. `在类说明符的结束时,类被认为是完全定义的对象类型(3.9)(或完整类型)。 Within the class member-specification, the class is regarded as complete within function bodies, default arguments and constructor ctor-initializers (including such things in nested classes). 在类成员规范中,该类在函数体,默认参数和构造函数ctor-initializers(包括嵌套类中的这类事物)中被视为完整。 Otherwise it is regarded as incomplete within its own class member-specification. 否则,它在其自己的类成员规范中被视为不完整。

Don't know what is UINT16 , but the following should work 不知道什么是UINT16 ,但以下应该有效

template<class T> 
class CClass 
{ 
private: 
    typedef struct { 
        T *mValue; 
        T *next; 
        T *previous; 
        short int index;                      // Replacing with int for illustration only
    } SValue; 
public:
    SValue* getNewSValue(void); 
private: 
}; 

EDIT 3: The *** came there trying to make the change BOLD (which I should have deleted anyways) 编辑3: ***来到那里试图改变BOLD(我应该删除它)

template<class T> typename CClass<T>::SValue* CClass<T>::getNewSValue(void) 
{ 
    return new SValue; 
}

int main(){
    CClass<int> s;
    s.getNewSValue();
}

Since the member function definition is in global scope, you need to qualify its return type with CClass:: to refer to the name within class scope. 由于成员函数定义在全局范围内,因此需要使用CClass::限定其返回类型以引用类范围内的名称。 Also, the typename keyword is needed when referring to typenames nested within templates. 另外,当引用嵌套在模板中的类型名时,需要typename关键字。

template<typename T>
typename CClass<T>::SValue* CClass<T>::getNewSValue(void)

Also, the nested struct is unnamed. 此外,嵌套结构是未命名的。 Note that in C++, classes and structs have proper names, and a typedef name is not a class name. 请注意,在C ++中,类和结构具有正确的名称,并且typedef名称不是类名。 You will be much better off avoiding the typedef. 避免使用typedef你会好得多。

struct SValue {
    T *mValue;
    T *next;
    T *previous;
    UInt16 index;
};

It looks like your struct is not defined when you declare the return type of getNewSValue . 当您声明getNewSValue的返回类型时,看起来您的struct getNewSValue

With that you don't have that error: 有了它你没有那个错误:

template<class T>
class CClass
{
public:
    SValue* getNewSValue(void);
private:
    typedef struct {
        T *mValue;
        T *next;
        T *previous;
        UInt16 index;
    } SValue;
};

template<typename T>
SValue* CClass<T>::getNewSValue(void)
{
  return new SValue;
}

And you also have to qualify the SValue return type, because it is nested in CClass when you use it to define getNewSValue . 你也有资格的SValue返回类型,因为它是嵌套在CClass当你用它来定义getNewSValue

Declare SValue before getNewSValue() : getNewSValue()之前声明SValue

template<class T> 
class CClass 
{ 
private: 
    typedef struct { 
        T *mValue; 
        T *next; 
        T *previous; 
        UInt16 index; 
    } SValue; 
public: 
    SValue* getNewSValue(void); 
}; 

Also, make sure UInt16 is defined. 另外,确保定义了UInt16

how about trying this ? 试试这个怎么样? it worked on VS2008 它适用于VS2008

template<class T>
class CClass
{
private:
    typedef struct {
        T *mValue;
        T *next;
        T *previous;
        __int16 index;
    } SValue;

public:
    SValue* getNewSValue(void)
    {
        return new SValue;
    }
};

The SValue-Type is inside the CClass-namespace. SValue-Type位于CClass-namespace中。 You need to fully qualify the typename outside the class. 您需要完全限定类外的类型名称。

template<typename T>
CClass<T>::SValue* CClass<T>::getNewSValue(void)

Also, you should make SValue public, if it is returned by a public method. 此外,如果公共方法返回SValue,则应将其公之于众。

For the record, none of these will compile (on GCC 4.2 at least) as soon as a call to getNewSValue() is called. 对于记录,一旦调用getNewSValue()调用,这些都不会编译(至少在GCC 4.2上)。 Since it's a public method that returns a pointer to a private type, you'll get a compile error stating that SValue is private . 由于它是一个返回指向私有类型的指针的公共方法,因此您将收到一个编译错误,指出SValue is private

In order for this to work, you'll either need to make SValue public, or change the type of the return value of getNewSValue() to something like void* , since it seems you're trying to make SValue an opaque type. 为了实现这一点,你需要公开SValue,或者将getNewSValue()的返回值类型更改为void* ,因为看起来你正试图让SValue成为一个不透明的类型。

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