[英]how to shift a datetime object by 12 hours in python
Datetime objects hurt my head for some reason. 由于某种原因,日期时间对象伤害了我的头。 I am writing to figure out how to shift a date time object by 12 hours.
我正在写作如何将日期时间对象移动12小时。 I also need to know how to figure out if two date time object's differ by say 1 minute or more.
我还需要知道如何确定两个日期时间对象是否相差1分钟或更长时间。
The datetime
library has a timedelta
object specifically for this kind of thing: datetime
库有一个timedelta
对象专门用于这种事情:
import datetime
mydatetime = datetime.now() # or whatever value you want
twelvelater = mydatetime + datetime.timedelta(hours=12)
twelveearlier = mydatetime - datetime.timedelta(hours=12)
difference = abs(some_datetime_A - some_datetime_B)
# difference is now a timedelta object
# there are a couple of ways to do this comparision:
if difference > timedelta(minutes=1):
print "Timestamps were more than a minute apart"
# or:
if difference.total_seconds() > 60:
print "Timestamps were more than a minute apart"
You'd use datetime.timedelta
for something like this. 你可以使用
datetime.timedelta
的东西。
from datetime import timedelta
datetime
arithmetic works kind of like normal arithmetic: you can add a timedelta
object to a datetime
object to shift its time: datetime
算法类似于普通算术:你可以将timedelta
对象添加到datetime
对象以转移它的时间:
dt = # some datetime object
dt_plus_12 = dt + timedelta(hours=12)
Also you can subtract two datetime
objects to get a timedelta
representing the difference between them: 您还可以减去两个
datetime
对象以获得表示它们之间差异的timedelta
:
dt2 = # some other datetime object
ONE_MINUTE = timedelta(minutes=1)
if abs(dt2 - dt) > ONE_MINUTE:
# do something
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